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plane is launched off ship from 0mi/h to 175 mi/h in 2.50 seconds. the velocity i get is 70. but i cant figure ot the distance traveled. please help.

2006-09-08 16:05:00 · 7 answers · asked by Anonymous in Education & Reference Homework Help

plane is launched off a carrier. In 2.50 seconds the plane is traveling at 175 miles per hour. The constant velovity is 70 and the acceleration is 0. figuring constant velocity, calculate the number of feet the plain traveled in the 2.5 seconds.

2006-09-08 16:16:33 · update #1

7 answers

I don't understand which velocity is 70

the starting velocity was 0 and the ending velocity was 175 mph
the velocity was every value between 0 and 175 during the launch

if we assume that the acceleration was constant (which the problem doesn't state) then we can calculate that

then if you use the formula, you can calculate distance

start with v=at
or a=v/t

a=175 m/hr/(*2.5/3600 hr)

a= 252000 m/hr^2

then

d=1/2 at^2

plug in a and t and you will get distance

d=1/2 (252000) mi/hr/hr (2.5/3600 hr)^2
d=.06 miles
or 320 ft

i did that quickly, you better check my math
and you probably should check those formulae I got out of my head

its been awhile since I did a lot of ballistics calculation

2006-09-08 16:22:52 · answer #1 · answered by enginerd 6 · 0 0

Except that in the first part of the question, the plane is accelerating and the terminal velocity is 175 mph. Acceleration (a) is v/t which gave you the 70. d=vt and v=at so we have d=(at)t. I can't derive the proof anymore, but I remember that because it was an acceleration problem, the right side of the equation had to be divided by 2 so that it becomes d=((at)t)/2. I'll let you complete the math.

2006-09-08 23:19:18 · answer #2 · answered by St N 7 · 0 0

Use the Velocity Time & Distance Ultra Calculator
http://www.1728.com/velocity.htm

2006-09-08 23:12:41 · answer #3 · answered by Anonymous · 0 0

According to this website : http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html it's Velocity = distance divided by time. So. Using your numbers, it would be

70 = D/2.5, solving for D. Hope that helped.

2006-09-08 23:13:04 · answer #4 · answered by Lynn E 1 · 0 0

velocity= distance / time

so use velocity times time=distance
just plug in the numbers

2006-09-08 23:14:19 · answer #5 · answered by Azary1010 3 · 0 0

velocity = distance x (time)

so, distance = velocity / time

2006-09-08 23:09:03 · answer #6 · answered by angel4lyfe 1 · 0 0

hes wrong... avg velocity is distance / time

so distance is velocity * time

2006-09-08 23:13:52 · answer #7 · answered by Anonymous · 0 0

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