solve the linear system of the two equation: y = 3x - 19, y = -1/3x+1
2006-09-08 14:17:29 · 10 answers · asked by yom b 1 in Science & Mathematics ➔ Mathematics
X=6, Y=-1
2006-09-08 14:24:15 · answer #1 · answered by nathan75932 6 · 1⤊ 1⤋
y= -1 x=6
2006-09-08 21:31:11 · answer #2 · answered by boj12345 2 · 1⤊ 0⤋
you are trying to isolate the variables
y=-1/3x +1
well the two equations are both equal to y so that means that they are equal to each other
which means 3x-19=-1/3x+1
add 19 to both sides
3x = -(1/3)x +20
add (1/3)x to both sides
(10/3)x = 20 (recall that 3x is equal to 9x/3
10x/3= 20 (mutiply both sides by three to get rid of the fraction on the left side)
10 x = 60
x=6
now you go back to the equation and plug in x to find y
y = -(1(6)/3)+1
y=-1
check with the other equation
y = 3x - 19,
3x= 18 if x= 6
18-10 = -1
since the answers match
x must be 6 and y must be negative 1
2006-09-08 23:43:40 · answer #3 · answered by applejacks 3 · 0⤊ 0⤋
3x-19 = -(1/3)x +1
add 19 to both sides
3x = -(1/3)x +20
add (1/3)x to both sides
(10/3)x = 20
x = 6
2006-09-08 21:27:28 · answer #4 · answered by KrautRocket 4 · 0⤊ 0⤋
y = -1/3x + 1
Multply both sides by 9
9y = -3x + 9
y = 3x - 19
Add these last 2 equations together
10y = 10
Divide both sides by 10
y = 1
I'm sure you can figure out x by yourself now :-)
2006-09-08 21:24:51 · answer #5 · answered by Demiurge42 7 · 0⤊ 2⤋
omg i hate algebra1. im taking it, too. no chance ill solve that though, lol. ive got my own equations to solve
2006-09-08 21:23:40 · answer #6 · answered by Kait 2 · 0⤊ 2⤋
What do you want to do Solve for X, what? Be specific
2006-09-08 21:23:04 · answer #7 · answered by sur2124 4 · 0⤊ 1⤋
Too simple
2006-09-08 21:23:35 · answer #8 · answered by pathowiz 3 · 0⤊ 2⤋
Why don't you solve it?
2006-09-08 21:24:22 · answer #9 · answered by Jim S 5 · 1⤊ 0⤋
honey, not to be mean, but....DO YOUR OWN HOMEWORK!
www.math.com
that should help. blessed be.
2006-09-08 21:24:53 · answer #10 · answered by Ravenfire 3 · 0⤊ 1⤋