find the width of the rectangle
2006-09-08 13:37:38 · 6 answers · asked by bengali_girl143 2 in Education & Reference ➔ Homework Help
let L be length P permimeter and W be width
L=8+2w
P=64
P=2L+2W
64=2(8+2W)+2W
64=(16+4W)+2W
64=16+6W
64-16=6W
48=6W
48/6=W
8=W
there ya go :) Hope that helped
2006-09-08 13:52:31 · answer #1 · answered by imjustme 2 · 0⤊ 0⤋
Assign x equal to the width hence 2[(8+2x)+X]=64 solve for x which comes out to 8 .
2006-09-08 21:17:32 · answer #2 · answered by dogpatch USA 7 · 0⤊ 0⤋
The width = 8
Length = 24
2006-09-08 20:53:17 · answer #3 · answered by Bonnie G 4 · 0⤊ 0⤋
If the length is (2x+8) and the width is (x).... then the equation becomes 6x+16=64. (two lengths and two widths). Solving gives an answer of 8 for the width
2006-09-08 20:41:24 · answer #4 · answered by camarochic 2 · 0⤊ 2⤋
One long side + one short side = 32 inches
long = 2 * short + 8
(2 * short +8) + short = 32
3 * short + 8 = 32
3 * short = 24
short side ( width ) = 8 inches
2006-09-08 20:50:47 · answer #5 · answered by millowner87 2 · 0⤊ 0⤋
L = 2W + 8
L * W = 64
simple substitution gives you
(2W + 8) * W = 64
solve for W. That will give you the width.
2006-09-08 20:42:32 · answer #6 · answered by Gypsy Girl 7 · 0⤊ 1⤋