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x= ln(t) , y=sqrt(t) , t> or = to 1.

2006-09-08 12:19:33 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Solve the first equation for t:
t = e^x

Solve the second equation for t:
t = y^2

Equate the two:
y^2 = e^x

Solve for y:
y = sqrt(e^x)

[ or alternatively y = e^(x/2) ]

2006-09-08 12:20:58 · answer #1 · answered by Puzzling 7 · 1 0

I always spend my half an hour to read this blog's posts daily along with a mug of coffee.

2016-08-23 06:25:52 · answer #2 · answered by ? 4 · 0 0

x= ln(t) implies t = e^x

substituting in y=sqrt(t) , we get y = e^(x/2)

or y^2 = e^x

2006-09-08 16:48:48 · answer #3 · answered by qwert 5 · 2 0

Perhaps, but I'm not 100% on it

2016-08-08 14:34:34 · answer #4 · answered by ? 3 · 0 0

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