He often says in the public, "I play every game like it is my last. I give my 110% when I am out there playing on the court." Whenever I see him playing on the court, he really plays like what he says.
He drives to the hole, gets knocked down but keeps coming back. He also dives for every loose ball. It makes me think he has total disregard for his body and is willing to play through pains, injuries to help his team win. As a basketball fan, I think he is a true warrior with the biggest heart although he may be the smallest player in the NBA. I have 2 Qs.
1. Where does his extraordinary energy and drive come from?
2. Do you think it is wise for him to play tough like he does? Should he drive less to the holes and dive less for the loose balls so he has less bruises, injuries which might prolong his playing career?
2006-09-08 10:50:48 · 9 answers · asked by nicesinging1 1 in Sports ➔ Basketball
alright well let me just tell you he is definitely amazing but he isnt the smallest player in the NBA. I think that his drive just comes from loving the game, my bro and i play exactly like that. You love it so much you'll do whatever you want to win, you arent thinking about your pain when you're just doin what you love. when you play basketball nothing is on your mind, its an escape. He's also been playin just about all his life after he stopped with his football. i think its fine because if you dont give it your all you mine as well not try. he's just doin everything he can and kickin everyone's trash out there. i dont care how old he is he still rocks.
2006-09-08 14:19:28 · answer #1 · answered by bb_king_22 2 · 0⤊ 0⤋
He is a competitor, with the need to win. Win or lose he always gives his all. Look at the great players of the past, as well as ones starting out now who push. You will see that drive in their eyes also. Some people have more talent than others, but their drive makes up for it. Talent without that will to be the best or succeed, only makes you a very good player. With it, you are a great player. Remember Jordan heading to the hoop with his eyes fixed and his tongue hanging out, well that is what is called super determination.
2006-09-08 12:59:24 · answer #2 · answered by Taiping 7 · 0⤊ 0⤋
Iverson truly is one of the most competitive players in the league. An athlete's greatest asset is his mindset, and Iverson has that edge that makes him Hal of Fame material. That's what fuels his drive and that's his style of play. The only adjustment that should be made in his game is to allow his teammates to get involved in the game. Michael Jordan, Shaquille O'Neal, and others learned that they must allow others to get involved in order to win titles. With Iverson's injury history, it's even more important that he learns that. Iverson plays very hard, but he may never win a title because he often plays 1 on 5. He has two All-Star level teammates in Chris Webber and Andre Iguodala, but they need more involvement offensively.
2006-09-10 14:59:32 · answer #3 · answered by phoenixmg2000 3 · 0⤊ 0⤋
1. Some people just naturally have that competitive drive. Iverson is one of those people.
2. I think it is wise for him to play the way he does. If he changed his attack, then he wouldn't be Iverson. He can't shoot, so if he stops driving, he becomes a very small, marginal player.
2006-09-08 11:54:39 · answer #4 · answered by 13 3 · 0⤊ 0⤋
He loves the game and puts his effort into it. It is like the opposite of me and homework!!
2006-09-08 14:49:43 · answer #5 · answered by Rodriguez 2 · 0⤊ 0⤋
he is a great player. BUT he has a bad attitude. i think if he was in a better team he would do much better.
2006-09-09 09:17:59 · answer #6 · answered by persianempire6 2 · 0⤊ 0⤋
he likes to play basketball and he is getting payed real well
2006-09-08 16:55:09 · answer #7 · answered by Wade 5 · 0⤊ 0⤋
Ego..wants to be better than everyone else...the money & fame isn't enough
2006-09-08 10:55:47 · answer #8 · answered by Anonymous · 0⤊ 0⤋
well he has to play hard because his team sucks(no offence)
2006-09-08 12:15:27 · answer #9 · answered by tech 1 · 0⤊ 0⤋