2006-09-08 10:01:03 · 5 answers · asked by thatgirl_angela07 1 in Science & Mathematics ➔ Mathematics
Without having the sequence there is no answer.
2006-09-08 10:06:50 · answer #1 · answered by Barkley Hound 7 · 0⤊ 2⤋
An arithmetic sequence is a sequence of numbers where the difference between successive terms is constant. Call this constant d.
In other words
t(n)-t(n-1)=d for n > 1
or
t(n) = t(n-1)+d for n > 1
If t(1) is the initial term then
t(2) = t(1) + d
t(3) = t(2) + d = t(1) + d + d = t(1) + 2d
t(4) = t(3) + d = t(1) + 2d + d = t(1) + 3d
So you can see in general t(n) = t(1)+ (n-1)*d
2006-09-08 10:16:38 · answer #2 · answered by Andy S 6 · 0⤊ 0⤋
http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut54c_arith.htm
Corrent formula, with subscripts, down the page just a bit in the Arithmetic Sequence section.
2006-09-08 10:07:12 · answer #3 · answered by TechNeo 4 · 0⤊ 0⤋
If a is the first term and d is the common difference,
the answer is a + (n-1)d.
2006-09-08 10:51:01 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
a(n) = a1 + (n - 1)d
2006-09-08 10:09:45 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋