The concentration of carbon monoxide in an urban apartment is 82 µg/m3. What mass of carbon monoxide in grams is present in a room measuring 9 12 22 ft?
2006-09-08 09:00:31 · 3 answers · asked by Analiese C 1 in Education & Reference ➔ Homework Help
I'm assuming it should read "a room measuring 9 x 12 x 22 ft".
V = 9 * 12 * 22 ft = 2376 ft^3
1 cubic feet = 0.02832 cubic meters
2376 ft^3 = 67.2808 m^3
Mass of carbon monoxide = concentration * volume
Mass of carbon monoxide = 82 µg/m3 * 67.2808 m^3
Mass of carbon monoxide = 5517 µg = .005517 g (solution!)
2006-09-08 09:08:44 · answer #1 · answered by ³√carthagebrujah 6 · 1⤊ 0⤋
volume of the room=(9)(12)(22)cft
=(9)(12)(22)(0.0283) cubic meter
CO present
=(9)(12)(22)(0.0283)(82)micro gm
=5513.75 microgm
=5.51375milligram
=0.00551375 gram
2006-09-08 16:08:55 · answer #2 · answered by raj 7 · 1⤊ 0⤋
no clue explain better
2006-09-08 16:03:50 · answer #3 · answered by Anonymous · 0⤊ 0⤋