A cylindrical glass tube 94.96 cm long, sealed at one end, is filled with water. The mass of water needed to fill the tube is found to be 9.98 g. The density of water is 1.00 g/mL. Calculate the inner diameter of the tube in centimeters.
2006-09-08 08:40:29 · 4 answers · asked by Analiese C 1 in Education & Reference ➔ Homework Help
9.98 g H2O / 1 g/ml = 9.98 ml Volume in the tube.
1 cm^3 = 1 ml
V = 9.98 cm^3
V(cylinder) = pi * r^2 * l
9.98 = 3.14159 * r^2 * 94.96 cm
9.98 = 298.32564 * r^2
r^2 = 0.033453 cm^2
r = 0.18290 cm
d = 2r = 0.36580 cm (solution!)
2006-09-08 08:49:16 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
It's real simple. You know the total mass of the water and its density. From those you can calculate the total volume, in mL. Keep in mind that 1 mL is equal to 1 cm^3. Dividing by the length of the tube will result in its cross-sectional area. You can solve for the diameter from there.
2006-09-08 15:54:25 · answer #2 · answered by czimme3 4 · 0⤊ 0⤋
you know the mass and density of water, so find the volume
then you know the length of the tube, so work backwards to calculate the diameter from the volume
2006-09-08 15:46:53 · answer #3 · answered by Ellen N 4 · 0⤊ 0⤋
volume of the cylinder=volume of water
so equationg
3.14*r^2*94.96=9.98
r^2=(9.98)/(3.14)(94.96)=0.0334cm
r=sq.rt.0.0334cm
r=1.8mm approximately
d=2r=3.6mm or 0.36cm
2006-09-08 15:47:59 · answer #4 · answered by raj 7 · 0⤊ 0⤋