I know this seems simple, but is the lim 3/x as x approaches 0 infinity??

Question

is there any algebra work to it?

thank you!!!!

Answer 1

well dear Kitty , for solving such a question like that you should do what am doing darling ;

f(x) = 3/x

a) lim 3/x = + ∞ { its right limit }
x –> 0+

b) lim 3/x = -∞ { its left limit}
x –> 0-

Its our correct answer.you can check it with your teacher as well.
Good Luck.

Answer 2

Think about it this way:

Start with a list of coordinates. And they don't have to be rea; bog/

x = 3, f = 1
x = 2, f = 3/2
x = 1, f = 3
x = 0, f = undefined
x = -1, -3
x = -2, f = -3/2
x = -3, f = -1

etc. You get the picture. So the numbers are getting dramatically smaller as you approach 0 from the negative side (limit is negative infinity) and the number approaching 0 from the positive side are getting dramatically bigger (limit is infinity). Hope this is helpful. And remember, when in doubt, just plot out some points.

Answer 3

Of course. 3/0 itself is undefined, but the closest you can get to 0 without the number being 0 is infinitesimal, and 3/infinitesimal=infinity. And no, it's not algebra so much as functions and graphing.

Answer 4

enable M = the minimize. Then ln M = ln (minimize as X techniques infinity (a million - 3 / x)^x ) = minimize as X techniques infinity ln (a million - 3 / x)^x = minimize as X techniques infinity x * ln(a million - 3 / x) = minimize as X techniques infinity ln [ (a million - 3 / x) ] / (a million/x) Use L'Hopital's Rule: lim x--> infinity [a million/(a million-3/x) *-3/x^2 / (-a million/x^2) ] = lim x--> inf of three/(a million-3/x) = 3 So ln M = 3 and the minimize is M = e^3

Answer 5

There are two possible answers.
If x approaches zero from the positive side the answer is +infinity
If x approaches zero from the negative side the answer is -infinity

The math involved is that outcome of a division approaches infinity as the denominator approaches zero (provided the numerator is not zero)

Answer 6

Yes because 3/0 is undefined

Answer 7

No, this is one of the few justifiable math questions I have seen.

I don't remember calc well enough to help or answer this, but this is a good question.

Answer 8

Yes!

Answer 9

abso - f'n - lutely