your stating point of motion was on earth ,now the observer on earth will see that you as you traveltime has dilated and your your distance traveled has contracted(per time dilation and lenght contraction formula) He we see your velocity as zero dived by long time diltation .Hence zero velocity means he sees you standing Still?
2006-09-08 07:27:09 · 10 answers · asked by goring 6 in Science & Mathematics ➔ Physics
Isnt velocity measured from a starting point of motion which is THE FRAME OF REFERENCE?
2006-09-08 07:45:06 · update #1
Suppose you return to earth and you shine a powerfull beam of light aim ed ate the observer,your motion being at light speed you are moving along with the light can the obseverver distinguish you from the motion of the light?
2006-09-08 07:53:28 · update #2
Pretend that the person moving near the speed of light is carrying a clock, a mirror and a flashlight. Further, pretend the person goes zipping past you and for some reason you are able to percieve them perfectly with your super-physo-vision goggles.
Now, as they go zipping right past you, they turn on the flashlight and point it straight up at the mirror they are holding. What kind of path do each of you see the photons of light travel? The person that is zipping past and turned on the flashlight sees the photons go up, hit the mirror, and come back down.
You see the photons take a different, longer path, because they seem to be moving sideways as well as up and down.
The fundamental premise behind the dilation equations is that both of you see the light going the same speed. Recall that d = rt and that r is fixed. If you see the light travel a longer path:
d1 = r * t1 and d2 = r * t2, then your time must be larger than their time. The clock that he is carrying is ticking slower than your clock.
Does this mean that you wouldn't see him move? No, he is still zipping past you. Are the hands of the clock he is carrying moving slower? Yes, that is what it takes to solve the time/distance paradox.
2006-09-08 07:59:16 · answer #1 · answered by tbolling2 4 · 1⤊ 0⤋
No. Your distance travelled does not dilate. If you are moving "near lightspeed," why would you contradict that and say your velocity is zero? You are clearly confused. There are many good books out there very readable by bright high school students. For a VERY thorough explanation, try Lillian Lieber's "The Einstein Theory of Relativity." She'll take you right through the proof of the Lorentz-Fitzgerald Contraction and on into beginning tensor calculus. And there are many much simpler.
2006-09-08 07:36:20 · answer #2 · answered by Philo 7 · 1⤊ 0⤋
Ah, good old Einsteinian thought experiments. Fun.
Like some of these other folks have said, The time dilation is not apparent to a stationary observer. He/she would see you zip off into the unknown at light speed, while most likely soiling their undergarments in disbelief.
Never race a photon.....you'll lose every time.
2006-09-08 07:54:20 · answer #3 · answered by Binary Buzz 1 · 0⤊ 0⤋
time dilation ONLY occurs for you. to the relatively stationary observer, time is still moving at normal speed and distance is unchanged. therefore, the observer on earth would see you as moving VERY fast
2006-09-08 07:35:33 · answer #4 · answered by promethius9594 6 · 0⤊ 0⤋
hi Pete - the area is that you replaced your inertial body contained in the technique the question. You began with the help of pointing out that each visitor replaced into shifting at 0.9c in opposite instructions - yet relative to what inertial body? then you definately suggested that the inertial body replaced into connected to visitor A. once you probably did that, the relationship between both visitors replaced, because you may want to state relative velocities in words of one body of reference. once you do this and keep on with the Lorentz rework equations as defined above, you discover that no merchandise can attain the speed of light relative to a distinct observer in any body of reference. such issues as measured time period and measured length interior the inertial body change with the intention to make this all authentic.
2016-11-25 20:50:44 · answer #5 · answered by mckuhen 4 · 0⤊ 0⤋
Not true. The observer will still see you moving at a speed very close to light; but if he were able to look at you very closely it would appear that you were moving very slowly in your reference frame. For example, if you were dringking a cup of milk it would seem to the observer that you were doing it in supe slow motion--in spite of the fact that your entire body woud still be moving by a a fantastic speed.
2006-09-08 07:34:38 · answer #6 · answered by bruinfan 7 · 0⤊ 2⤋
No, an observer would see you moving away from them at the speed of light (which they wouldn't be able to see anyway).
Relative motion, like, say you moving your arm, they would not be able to see. You would appear like you arn't moving any of your body parts, but you would not be standing still.
2006-09-08 07:31:48 · answer #7 · answered by Anonymous · 0⤊ 2⤋
I see - so, if I move away at the speed of light I could rush into the kitchen and make myself a nice cup of tea before I arrived there?
Is that what you are saying?
2006-09-08 07:33:29 · answer #8 · answered by Anonymous · 0⤊ 2⤋
ur velocity will be zero only when the observer is also moving at light speed.not when he is stationary.
2006-09-08 07:31:21 · answer #9 · answered by thegr8one 1 · 0⤊ 2⤋
if you moved at went back at the spot they would se you standing still, but if you run away, you would just suddenly have dissappered
2006-09-08 07:30:58 · answer #10 · answered by Unbekümmert 4 · 1⤊ 1⤋