Of course, there's more than one way to do it, but any way you do it should give equivalent answers. I'd start with your expression
(6x + 4x – 10) - (4x - 6x + 4)
and first simplify what's inside the parentheses by adding (or subtracting) terms with x's
(10x - 10) - (-2 x + 4)
then get rid of the parentheses
10x - 10 + 2x - 4
then add terms with x's and terms without x's
12x - 14
and that's probably where I'd stop.
2006-09-08 04:58:33
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answer #1
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answered by btsmith_y 3
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Assuming you don't mean
(6x^2 + 4x - 10) - (4x^2 - 6x + 4) = 2x^2 + 10x - 14
(6x + 4x - 10) - (4x - 6x + 4) =
(10x - 10) - (-2x + 4) =
10x - 10 + 2x - 4 =
12x - 14
2006-09-08 16:51:56
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answer #2
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answered by Sherman81 6
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(6x + 4x - 10) - (4x - 6x + 4)
(10x - 10) - (- 2x + 4)
Collecting like terms inside the parenthesis
10x - 10 + 2x - 4
Removing parenthesis
10x + 2x - 10 - 4
Collecting like terms
12x - 14
2006-09-08 14:49:58
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answer #3
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answered by SAMUEL D 7
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The - outside the second set of parentheses changes all three terms inside to their opposite. So you have:
6x + 4x - 10 - 4x + 6x - 4
Then combine like terms to get 12x - 14
2006-09-08 11:53:56
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answer #4
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answered by hayharbr 7
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First add all common terms within the parentheses; then add all common terms.
(6x+4x-10)-(4x-6x+4)=
(10x-10)-(-2x+4)=
12x-14
2006-09-08 12:53:42
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answer #5
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answered by Rachel M 2
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(6x + 4x - 10) - (4x -6x + 4) =
(10x - 10) - (-2x + 4) =
10x - 10 + 2x - 4 =
12x - 14
2006-09-08 14:53:58
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answer #6
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answered by Dimos F 4
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(6x + 4x – 10) - (4x - 6x + 4)
Simplify the brackets first
=(10x-10) -(-2x+4)
Open brackets, please note that negative sign is out side therefore chage sign of all
=10 x - 10 + 2x -4
=12x -14
2006-09-08 11:54:59
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answer #7
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answered by Amar Soni 7
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6x+4x-10-4x+6x-4
12x-14
2006-09-08 11:52:12
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answer #8
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answered by dan 4
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the method is to bring the x terms and constants together
so
it is 10x-10-(-2x+4)
= 10x - 10 + 2x -4
= 10x+2x -(10+4)
= 12x-14
2006-09-08 12:01:17
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answer #9
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answered by Mein Hoon Na 7
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thas 10x-10) - (-2x + 4)
10x - 10 + 2x -4
12x -14
2006-09-08 11:59:09
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answer #10
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answered by weirdoonee 4
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