i have a rock under the sea water and it weigh 1 kg , how many cube cm of air it required to take it up ?

Question

to take this component up to sea bed

Answer 1

About 970 to 981 cc will just lift the rock to the surface, assuming 1 kg is its weight in water (not in air). This includes the 1 cc for the air's own weight, as answer 1 pointed out is also necessary. (Actually it's about 1.3 cc to provide 1.3 g of buoyancy, since 1 mole of any gas including mixtures like air displaces 22.4 liters, and air's molecular weight is about 29; thus 1 liter of air weighs 29/22.4 g.) The weight of the air container will require more air to lift it, but you didn't specify that weight. This assumes the air container is rigid; otherwise the pressure at depth will compress the air so it displaces less water resulting in less buoyancy, the Cartesian diver effect. Seawater has a density at the surface of 1.020 to 1.029, and tends to be denser as depth increases (see ref.).

Answer 2

One litre (1000 millilitres) weighs precisely 1000 grams provided that it relatively is at precisely 21 tiers celcius and it extremely is been purified and deionised. Sea water, as stated above, has many impurities and dissolved solids in it. it extremely is mass (there is no such subject as weight - it relatively is in user-friendly terms a handy way for the lay guy or woman to comprehend the complexities of the physics in contact) additionally relies upon plenty on the temperature, yet in user-friendly terms once you get into the milligram variety of issues... so the quick answer isn't any. A litre of sea water could be at an uncomplicated temperature of roughly 25 tiers so it may weigh greater like 1003.8 grams. desire this helps! Love and lightweight, Jarrah

Answer 3

Up to sea surface, I think you mean. Approximately 1001 cubic cm of air will do it - 1000 of them to lift the rock, and 1 more to lift the first 1000 of air (air weighs about a thousandth of water).