i need serious help with math! List the possible rational roots of f(x)= x^3 - x^2 - 10x - 8!?

Question

i am very bad at math and im pregnant and trying to do school work before the baby gets here and it is hard!

Answer 1

This is probably a problem dealing with the rational root test. If you have a polynomial with a rational root p/q, then q divides the coefficient of highest degree and p divides the constant coefficient. For your example, the highest degree coefficient is 1 (the coefficient of x^3) and the constant coefficient is -8. So q would have to divide 1, which means it is either 1 or -1. The numberator, p, would have to divide -8, so would be 1,2,4,8, or -1,-2,-4,-8. Now look at all possible combinations p/q from these lists. This gives the possible rational roots to your polynomial:
p/q=1,2,4,8,-1,-2,-4,-8.

Now, you still have to check to see whether these are *actual* roots. In your case, you find that -1,-2, and 4 are roots.

Answer 2

If you didn't mistyped then the constant factor is:
8! = 1*2*3*4*5*6*7*8 = 40320
and the possible roots are the numbers +/-(1, 2, 3, 4, 5, 6, 7, and 8)

Answer 3

x^3 - x^2 - 10x - 8 / x + 2 = x^2 - 3x - 4 so one of the roots is x1 = -2

For the other roots, resolve for x^2 - 3x - 4

You'll get x = ( 3 ± sqrt( 9 +16) ) /2

x2 = 4 , x3 = -1

-8 - 4 + 20 - 8 = 0
64 - 16 - 40 - 8 = 0
-1 - 1 + 10 - 8 = 0

Answer 4

Except that Mathematician mispelled "numerator," he's exactly right. Ignore the rest of the answers. The rational root test is a standard topic in Alg 2, Precalc, and College Algebra.

Answer 5

f (x) = x³ - x² - 10x -8

- - - - - - - - - - - - - - - - - - - - -

x = -1

f (-1) = (-1)³ - (-1)² - 10(-1) - 8

= -1 -1 + 10 - 8

= - 10 + 10

= 0

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

x = - 2

f (- 2) = ( -2)³ - ( -2)² -10(- 2) - 8

= -8 -4 + 20 - 8

= -20 + 20

= 0

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

x = 4

f (4) = (4)³ -(4)² -10(4) -8

= 64 - - 16 - 40 - 8

= 64 - 64

= 0

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

The roots are

-1, -2 and 4

Answer 6

if the x3 = x exponent 3 please write is as x^3 firstly, i will assume that this is what you meant... use the B/A formula where 4 will be your B and the coefficient of your highest power will be your A values find the factors of your B value.....1,-1,2,-2,4,-4 are your factors. find factors of A value.....+1, -1 are the only possible. B/A now... you can have 1,-1,2,-2,4,-4 after..... sub in these values for X in your equation... if it equals to zero then it is a factor....example. f(1)=0 therefore (x-1) is a factor divide synthetically after with 1.

Answer 7

I just went to my favorite function grapher and plotted it.

It crossed the x axis at -2, -1 and +4, so those are the rational roots (aka rational zeroes).

Answer 8

f(x)=x^3-x^2-10x-8
By trial,
when x=-1,
f(-1)=(-1)^3-(-1)^2-10(-1)-8
=0
Hence,

f(x)=(x+1)(x^2-10x-8)
=(x+1)(x+2)(x-4)

When f(x)=0,
x=-1,-2,4

Answer 9

You can plot the graph and where the line crosses the x-axis, that is when the funcion equals zero, hence your solutions

Answer 10

=Do your homework yourself