An almost easy Q , Who can answer ?!?!?!?

Question

find the answer :
(3x^2-3x)/(x^3)>1

Which of the following can be the answer ?!?!?!
1) |R - {1}
2) { }
3) { x | x>1 }
4) { x | x<1 }

Answer 1

Easiest way in these situations is to try different numbers
say x=3
then then answer is 2/3, so that rules out options 1 and 3
now say x=0.5, then we get -6, so that rules out option 2, and we are left with 4.

Answer 2

3

Answer 3

Simplify the equation and you will get x^2-3x+3<0

Derive the first derivative and you will find that it has a minimum at x=3/2, that is 3/4. Verify that this is a minimum by the second derivative (2>0).
Then, as you can see, the equation has no solution in the field of real numbers.
The correct answer is 2.

Answer 4

The answer is 3. Pick any value greater than 1 (Let's pick 2)

2 squared times 3 = 12. 12 - 6 = 6* 2^3 (8) 48

48>1

Answer 5

First the definition filed excludes zero, so it is |R - {0}.
After some operations you get:
x^2 - 3x + 3 < 0, which is TRUE for every x (because b^2 - 4ac < 0 and a > 0). So the answer is:
|R - {0}

Answer 6

3x(x-1)/x^3 > 1 =>
3(x-1)/x^2 > 1 =>
if x = 1 then No Answer
if x = 4 then Result = 1
if x < 1 then -/+ => - Result < 0 => - Result < 1
if x > 1 then Result < 1

so the answer is {} = Null = (2'nd Choice)

Mage ye Irooni Javabeto Bede :D

Answer 7

take 3x common
3x(x-1)/x^3 >1 divide by 3 and cancel x from both
(x-1)/x^2 >1/3
denominator always >0
so x-1 >1/3
so x>4/3
so non of above

Answer 8

i go 4 number 4

Answer 9

absolute 4

|4|

Answer 10

is it so easy that you are trying to get someone else to tell you the answer?