what is the way of calculating meeting point of two objects coming toward eachother from opposite directions

Answer 1

Alrighty, dighty, assuming that we observe the two objects traveling at constant velocities for a period of time, t, until they meet, and

Object 1 travels distance d1, traveling at speed v1
Object 2 travels distance d2, traveling at speed v2
The total starting distance between them is D
then:

d1 = v1 x t
d2 = v2 x t
D = d1+d2

You need some of the values to start with and you can find the rest of them with these three nifty equations. If the objects change speed during their travels, it gets a bit more complicated. You then have to figure the distances traveled over time segments and add them up, or use an acceleration formula to get the distance traveled. Good luck!

Answer 2

s1=distance object one travels before the two objects meet
s2=distance object two travels before the two objects meet
sT=Total distance objects are appart at start of journey
v1=velocity of object 1
v2=velocity of object 2
velocity = displacement / time
therefore time=displacement /velocity
or t=s/v
t1=s1/v1
t2=s2/v2
but...
We know that the two objects will meet at the same time, so t1=t2
hence s1/v1=s2/v2
We also know that if object 1 has traveled a distance of s1, object 2 will have travelled a distance of sT-s1
Hence s1/v1=(sT-s1)/v2
solving for s1

s1v2=sTv1-s1v1
s1v2+s1v1=sTv1
(v2+v1)s1=sTv1
s1=sTv1/(v2+v1)

distance traveled by object 1 = the starting distance between the two objects multiplied by the velocity of object 1 divided by the sum of velocities of objects 1 and 2.

You can work out the other distance. s2 = sT-s1

its much safer to actually swerve out of the way of oncoming traffic then to try and work this sum out in your head while driving.

Answer 3

The meeting point if the objects depends apon the speed of the objects.

Answer 4

The train coming from Cleveland will travel the same elapsed time as the train leaving Topeka.

If one is traveling 60 mph, and the other is doing 100 mph, the 100 mph train will travel 1.666 times farther than the slower train.

Answer 5

v1 = velocity of object 1
v2 = velocity of object 2
t = time
d = distance apart

so t*v1 + t*v2 = d , we know d, v1 and v2 so solve for t. Then the meeting point is t*v1 from the start point of object 1 or t*v2 from the start of object 2.

Answer 6

calculate velocities of the two objects, then add them - if you reach zero, than your d value is the meeting point.

Answer 7

Try to solve Time & Distance, problems, in Mensuration.

Answer 8

i don't know