2006-09-07 22:57:32 · 6 answers · asked by dickster00 1 in Science & Mathematics ➔ Physics
No.
If they are in exactly opposite directions then they must be equal to give zero resultant.
If they are not in exactly opposite directions then one of them could be resolved into two directions leaving a resultant.
eg: One vector is horizontal and a second one acting at an angle to it in an opposite direction. It could be possible that the second would have a horizontal component equal and opposite to the first, but the second would still have an unbalanced vertical component making equilibrium impossible.
2006-09-08 00:16:18 · answer #1 · answered by hippoterry2005 3 · 0⤊ 0⤋
if by 'unequal' you are disregarding the sign (+ve/-ve) then no.
5N <---x---> 5N
the resultant of the forces on the above block 'x' is 0 but the forces are equal (but in opposite directions).
this is the only way to give a zero resultant with two forces (vectors).
you could have a situation with three vectors and a zero resultant (with any two forces being unequal) but i don't think this is what you're looking for.
2006-09-07 23:05:02 · answer #2 · answered by Eatthefrog 2 · 0⤊ 0⤋
sure on condition to multiplie them with corresponding numbers so that:
a.v+b.u=0 where u and v are the vectors
a & b u choose them to get the zero result...
e.g u can choose a=1/(norm of v), b= -1/(norm ofu)
norm(u)=somme((composant of u)^2)
2006-09-07 23:05:28 · answer #3 · answered by Rachel 1 · 0⤊ 0⤋
no,bcoz they wont be in the state of equilibrium,atleast i think so.
2006-09-07 23:10:57 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Go play SUMO.
2006-09-08 00:19:18 · answer #5 · answered by dwarf 3 · 0⤊ 0⤋
Stupid question. Rephrase.
2006-09-07 23:00:32 · answer #6 · answered by Mr Bean 1 · 0⤊ 0⤋