maths help?

Question

we're supposed to simplify the problems. help pls?

-11a^3 / 121a^2

7 [3(2x + 3y) - (x - 2y) - 5] + 8

7pq x (-5r) qr

Answer 1

-11a^3/121a^2 = -11a^2*a/11*11*a^2 (simplify)
= -a/11

7 (3(2x+3y) - (x-2y) -5) +8 (expand everything you need to)
= 7 * (6x + 9y -x + 2y) - 7*5 +8
= 7* (5x +11y) -35+8
= 35x + 77y -27

7pq x (-5r) qr (what do you want here?)
= -35.pq² r² ? (assuming x is the multiplication operator)


Next time: try doing it yuorself before asking, or you'll never learn and stay ignorant all your life.

Answer 2

(1)
first do the numbers.... -11/121. that is -11

then do a^3/a^2... if you remember you do subtraction if its a division problem with exponents. so do 3-2. so it is a^1 or just a

combine the two so it is -11a for the answer.
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(2)

for this one you need to simplify. do the inner ( ) first before you do the outer ones. you cant combine the different variables so just multiply by the coefficients. (it is easiest to take this in steps).

3(2x+3y) --> 3(2x) + 3(3y) = 6x+9y

that subtraction sign is the same as -1(x-2y) so you have to multiply across...

-1(x-2y) --> -1(x) -1(-2y) = -x+2y

now you should have 7((6x+9y) + (-x+2y) -5) +8

combine the like variables and numbers so you should get...
7(5x+11y-5) + 8

again multiply across (always multiply or divide before adding or subtracting)

7(5x) + 7(11y) + 7(-5) = 35x + 77y - 35

all you have to do now is just add in that extra 8 so your answer is...

35x + 77y - 27
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(3)

this next one is simpler than it looks. everything is just multiplying each other so just match up the coefficients and the variables so....

the -5 and 7 multiply to get -35 and there are 2 q's and 2 r's so you combine them and get q(q) and r(r) = q^2 and r^2

put them together and get -35q^2r^2p

Answer 3

The first one is easy
step 1, divide the fraction by 11 in the numerator and denominator, this basically cancels out the 11 and you are left with

-a^3/11a^2

Step 2
cancel out the powers so that you are left with
-a/11
(explanation a^3/a^2 = a^(3-2) = a^1 = a

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7 [3(2x + 3y) - (x - 2y) - 5] + 8
= 21(2x+3y) - 7(x-2y)-35+8 (you are opening the '[ ]' brackets
= 42x + 63y-7x+14y-35+8 (open the '( )' brackets and minus into minus is plus
= 35x+77y-27
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7pq x (-5r) qr

first open the '( )' brackets
= 7pq x -5qr^2 (as there is r x r, it becomes r^2)
then multiply

you get - 35pq^2r^2
(bascially you are carrying out7x5, px1, qxq, r^2, all preceded with a '-' sign

Answer 4

7

Answer 5

Divide both sides in first one by 11, then a

Answer 6

1. -a/11

2. 35x+77y-27

3. Still working ... a little confused because I might being making it more complicated.

Answer 7

I think I would work on my spelling too.

Answer 8

can't understand a number u're writing. sorry.

Answer 9

Please can you write down the equations clearly? then only we can answer. We are looking forward for your action.