xz^2+xw^2=xy^2+5
xz^2+xw^2-xy^2=5
x(z^2+w^2-y^2)=5
x=5/(z^2+w^2-y^2)
Too easy!
2006-09-07 20:14:22
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answer #1
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answered by uselessadvice 4
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The key to solving for one variable is isolating it. Recall the addition quality of equality..
if a = b then a - 5 = b - 5
well you have this xz^2 + xw^2 for an 'a' and a xy^2 + 5 for a 'b', right? then it stands to reason that we can subrtract that xy^2 term and it'd end up on the other side.
xz^2 + xw^2 = xy^2 + 5
is now
xz^2 + xw^2 - xy^2 = 5
Now let's use the distributive of numbers to get that x out of each of those terms on the left side.
The distributive property goes like this
a*c + b*c = c*(a+b)
This means that since there's an x in each term, we can just weed it on out of there and put parentheses around the whole group. Sorta like herding in the cattle!
x * (z^2 + w^2 - y^2) = 5
That big boy doesn't look so bad now, does it??
Now all we gotta do is make the x and the 5 switch places.
If we divide by x on both sides, we'll end up with
(z^2 + w^2 - y^2) = 5 / x
and then the inverse is
1 / (z^2 + w^2 - y^2) = x / 5
so multiply by 5 and you get
x = 5 / (z^2 + w^2 - y^2)
2006-09-07 21:10:14
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answer #2
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answered by Neisayer 2
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Solving for x
xz² + xw² = xy² + 5
xz² + xw² - xy² = xy² + 5 - xy²
Subtracting - xy² from both sides of the equation
x(z² + w² - y²) = 5
removing the common factor x from the equation
x(z² + w² - y²)/ (z² + w² -y²) = 5/(z² + w² - y²)
Dividing (z² + w² - y²) from both sides of the equation
x = 5/(z² + w² - y²)
2006-09-08 01:45:03
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answer #3
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answered by SAMUEL D 7
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xz² + xw² = xy² + 5
xz² + xw² – xy² = 5
x (z² + w² – y²) = 5
x = 5 ÷ (z² + w² – y²)
2006-09-07 20:18:07
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answer #4
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answered by Anonymous
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LMAO..I looked at the question...then said...5..I may be on the right track.
Purely by accident, unless I am some kind of mathamatical idiot sivante.
That is as opposed to just being a garden variety idiot.
Shine on
2006-09-07 20:16:38
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answer #5
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answered by Comfortably Numb 3
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if you don't understand Dan's answer, ^2 means squared. When typing on the computer use the carrot (is that right?) sign ^ followed by the power.
2006-09-07 20:14:55
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answer #6
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answered by Anonymous
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(x*y)+z*=w*+5
x*=y+z+w+5
x=4
this is an advanced finite mathematics formula which significantly simplifes the problem ..
now try to use this as a hlepfull way to solve your problem effectively
2006-09-07 20:15:52
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answer #7
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answered by Anonymous
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I hope you at least worked a little on this problem yourself before asking everyone else to do your homework for you...
2006-09-07 20:15:47
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answer #8
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answered by Anonymous
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x(z^2+w^2-y^2)=5
x=5/(z^2+w^2-y^2)
2006-09-07 20:11:54
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answer #9
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answered by dan 4
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x(z*+w*-y*)=5
x=5/(z*+w*-y*)
2006-09-07 20:17:04
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answer #10
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answered by fozerol 1
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