2006-09-07 19:42:36 · 6 answers · asked by Princess Jasmine 2 in Computers & Internet ➔ Programming & Design
The max number is actually 255. (2^8 - 1)
[1][1][1][1][1][1][1][1] in binary form
This is equivalent to - 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 in decimal.
There are 256 numbers however.
A Byte starts at 0, and goes to 255. This yields 256 total numbers.
8 Bytes is different. The max number in decimal is
18446744073709551615 (2^64) (the 64 is derived from 2^8 = 1 byte, so multiply the exponent by 8 more bytes to get 64)
The total number is 18446744073709551616
2006-09-07 19:50:54 · answer #1 · answered by Elian 2 · 3⤊ 0⤋
the max number of 8 bites is 16 and the total number is 64
2006-09-08 02:46:09 · answer #2 · answered by tekya 2 · 0⤊ 1⤋
Your question isn't clear for a variety of reasons. You'd need to clarify what you really are looking for, particularly in regards to "max" vs "total number".
8 bytes is equivalent to 64 bits (8 bits per byte * 8 bytes)
So the largest number that can be stored in 64 bits is 2 to the 64th - 1.
2006-09-08 03:02:28 · answer #3 · answered by Gizmo L 4 · 0⤊ 1⤋
2^8=256
That is, 2 to the power of 8 equals 256 bytes.
2006-09-08 02:44:49 · answer #4 · answered by Mr. Pheterson 2 · 1⤊ 0⤋
there is 64 bits in one bite sooooooooo, you have 512 bits
2006-09-08 02:50:31 · answer #5 · answered by mikeal w 1 · 0⤊ 1⤋
I don't understand your question.
7?
2006-09-08 03:00:19 · answer #6 · answered by sweets 6 · 0⤊ 1⤋