I'm sorry but i haven't done math in over ten years. I can't solve it even when i get to t. Please solve it completely.
2006-09-07 18:26:05 · 5 answers · asked by naya w 2 in Science & Mathematics ➔ Mathematics
Um....... no.
2006-09-07 18:28:55 · answer #1 · answered by ferdinand 3 · 0⤊ 0⤋
sqrt(x-7)*x^(1/4)=8
Then x=1/3*(14+(54953-192*sqrt(81915))^(1/3)+(54953+192*sqrt(81915))^(1/3))
=20.9744490138894967069696874298262733942...
Verify by substitution
There is only one solution. The complex roots one obtains from x^3-14*x^2+49x-4096=0 do not satisfy the initial equation (verify by substitution).
2006-09-08 01:38:35 · answer #2 · answered by tarahloft 2 · 0⤊ 0⤋
Sqrt[x-7] * Fourthroot[x] = Fourthroot[x*(x-7)^2]
Set this equal to 8 and you get x^3-14x^2+49x-4096=0
Solving you get only one real root of x and two complex conjugates.
2006-09-08 01:36:14 · answer #3 · answered by astrokid 4 · 0⤊ 0⤋
When you havent done Mathematcs in ten years,
who the hell asked you this question?
I'll tell you a simpler way, go learn Counting first!
2006-09-08 01:31:36 · answer #4 · answered by vandan 2 · 0⤊ 0⤋
Err... your question can be a lot of meaning... here are the list of possible question you want to ask.. Please confirm which one, so that we can assist in the more efficient way.
(x-7)^0.5 * x^0.25 = 8
or
(sqrt x - 7) * x^0.25 = 8
or
sqrt x - 7 * x^0.25 = 8
Which one is correct? All will give you different answer.
2006-09-08 05:24:25 · answer #5 · answered by Mr. Logic 3 · 0⤊ 0⤋