2(8y-7)=2(3+8y)
help!
2006-09-07 18:07:20 · 10 answers · asked by Anonymous in Education & Reference ➔ Homework Help
The question is wrong !!!!!
It suggest that no value of y can satisfy the equation bcoz of (1st and 2nd answers) those reasons
2006-09-07 18:35:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The answer is infinity (the number 8 laying on its side :-) See the solution below:
2(8y-7) = 2(3+8y);multiply it all out to get:
16y-14=6+16y;add 14 to both sides to get:
16y=20+16y;
...now DIVIDE both sides by y to get:
16=20/y +16; substract 16 from both sides to get
0=20/y; divide by 20 to get:
0=1/y
y = infinity...think about it; the larger the number on the bottom, the smaller the fraction. A fourth is smaller than a third is smaller than a half. So an infinitely large number on the bottom would make a fraction so small as to approach zero
2006-09-08 01:23:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋
If you work it out completely you get 20 = 0. Twenty obviously is not the same thing as zero, so generally when this occurs you simply write "no answer".
2006-09-08 01:23:22 · answer #3 · answered by spacemonkey32587 1 · 0⤊ 0⤋
16y-14=6+16y
16y-16y=14+6
0y=20
thats called: not possible
2006-09-08 01:28:57 · answer #4 · answered by baby 3 · 0⤊ 0⤋
16y-14=6+16y
transposingy vanishes so cannot be solved
2006-09-08 01:10:03 · answer #5 · answered by raj 7 · 2⤊ 0⤋
16y-14=6+16y
16y-20=16y
-20=0
not possible
2006-09-08 01:10:39 · answer #6 · answered by jinx12 3 · 1⤊ 0⤋
How interesting. There is no value of y that will satisfy this equation.
2006-09-08 01:18:27 · answer #7 · answered by ? 6 · 0⤊ 0⤋
zero
2006-09-08 01:10:47 · answer #8 · answered by Leo H 4 · 0⤊ 0⤋
zero
2006-09-08 01:21:27 · answer #9 · answered by flounder_bob@sbcglobal.net 2 · 0⤊ 1⤋
xzengo! 0000000000
2006-09-08 01:16:12 · answer #10 · answered by no 3 · 0⤊ 0⤋