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i dotn really get this kind of math. In a football game, Michael gained 134 yards runninh. this was 17 more yards more than the previous game. How many yards did he gain in both games. can someone please explain this to me

2006-09-07 17:52:38 · 6 answers · asked by Anonymous in Education & Reference Homework Help

6 answers

Michael Gained 134 yards running
// okay... why do we care about this?

This was 17 more yards than the previous game
// okay 17 MORE means we will add so:
YardsInPreviousGame + 17 = 134

Now you just solve for the variable by moving the 17 to the other side

2006-09-07 17:59:39 · answer #1 · answered by mdigitale 7 · 0 0

The standard letter to define a variable is X. You need to know the total yards he ran for both games, so the total yards will be defined as X. If the difference between the two games is 17 yards, you can say that X - 134 = 134 - 17

2006-09-07 17:57:36 · answer #2 · answered by spacemonkey32587 1 · 0 0

Sure. Let's define the variable first. Usually, you should look for the exact question in the whole problem and get the variable from that. Here the question is "How many yards did he gain in both games" so let's call that x. Then when we solve this whole mess for x you will have exactly the answer you need.

Now, Michael gained 134 yards in one game, and evidently gained 117 yards in the previous game.

x = 134 + 117 = 251

This question is so idiotically easy it can't be right. Go back, look at your homework assignment again, and ask the question correctly. Write an equation for "each" problem? What "each"?

2006-09-07 17:55:02 · answer #3 · answered by ? 6 · 0 0

OoOo this is easy.You know that...
He has 134 yards this game
This game was 17 more yards than the last game

Ok so lets make the last game as X. since the last game was 17 less than this game, the equation would be...

x=134-17

now u solve

x=134-17
x=117

Ok now that u noe that in the last game he had 117 and this game he has 134 yards, u add them

117+134=251 yards

In total he has 251 yards.




please mark as the best answer. Thank You. =]

2006-09-07 18:01:39 · answer #4 · answered by >???<Chinita>???< 3 · 0 0

hmm... if i get this question correctly.

first game = x (unknown)
second game = 134 yds.

in the first game he gained 17 fewer yards...

134 - 17 = 117

in two games he gained 117 + 134 = 251

or you can think about it this way...

let's say that he runs 134 yds in both games. that's 268 yds in both games. however, he ran for 17 fewer yards in the first game so subtract 17 from 268... 251

2006-09-07 17:58:55 · answer #5 · answered by need2know 2 · 0 0

2 the thanks to sparkling up: #a million: eliminating x+2y=0 2x-6y=5 Multiply equation a million with the help of utilising 3 3x+6y=0 2x-6y=5 -----------upload 5x=5 x=a million change a million for x into both of both unique equations. x+2y=0 a million+2y=0 2y=-a million y= -a million/2 #2: Substitution x+2y=0 2x-6y=5 From Equation No.a million, x=-2y replace x with -2y in Equation No.2 2(-2y)-6y=5 -4y-6y=5 -10y=5 y= -a million/2 As before, replace y with -a million/2 interior both unique equation. 2x-6y=5 2x-6(-a million/2)=5 2x+3=5 2x=2 x=a million Take your %.!

2016-11-25 20:10:13 · answer #6 · answered by ? 4 · 0 0

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