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√x-7 x 4√x= 8 I hope that is better. I haven't done math in years. I not sure how to use math.com or put the square root in.

2006-09-07 17:29:46 · 6 answers · asked by naya w 2 in Science & Mathematics Mathematics

6 answers

Taking 4th power on bothsides makes the equation as follows

x^3 - 14 x^2 + 49x - 4096 = 0

Solve this to get answer

2006-09-07 17:38:06 · answer #1 · answered by Truth Seeker 3 · 0 0

Take the fourth power of each side term by term.

[(x-7)^2].x=(2^3)^4

(x^2-14x+49)x=2^12

x^3-14x^2+49x-2^12=0

By trial and error method find one root.
Then use Horner method to find another roots.

Or use a computer program to find x values.
Or use excel for various values to estimate the values of x.

2006-09-07 17:39:16 · answer #2 · answered by iyiogrenci 6 · 0 0

you have to put both left and right sides to the power of 4.

then u will get

x(x-7)^2=4096
x(x^2-14x+49)-4096=0
x^3 - 14x^2 + 49x - 4096 = 0

2006-09-07 17:40:53 · answer #3 · answered by statistics 4 · 0 0

you don't say fourth square root
i think you just mean fourth root
(x^1/2-7)(x^1/4)=8
square both sides
(x+49-14X^1/2)(x^1/2)=64
x^3/2-14x+49x^1/2-64=0
let x^1/2 be t
t^3-14t^2+49t-64=0
now solve for t
and revert back to t=x^1/2

2006-09-07 17:40:39 · answer #4 · answered by raj 7 · 0 1

okey,squared all equation first.
Then put all x in one side, numbers on the other side,
simplify, then you should get the answer.
I think the final equation is
16x squared - 112x - 64 = 0
got two value of x..

2006-09-07 17:42:38 · answer #5 · answered by (^___^) 2 · 0 1

let y = sqrt(x), x = y^2

Square both sides:
(x-7)(sqrt(x))=64
(y^2-7)(y)=64
y^3-7y-64 = 0

2006-09-07 18:00:32 · answer #6 · answered by Anonymous · 0 0

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