a survey of 100 seniors at a high school reported 82 students taking a math course 33 taking a chemistry course 27 taking physics course.42 not taking any physics or chemistry course.if everyone taking science is also taking math .how many students are taking math ,chemistry , physics?
2006-09-07 17:10:30 · 9 answers · asked by Anonymous in Education & Reference ➔ Homework Help
I conclude possibly 2, but not proven.
Out of 100 students, 82 are in math
Out of 100 students, 42 are in no science at all. (no physics or chemistry). 100 - 58 = 42
This means that 58 ARE in physics and/or chemistry.
27 are in physics. 33 are in chemistry. 27 + 33 = 60.. 60 is NOT 58! A couple of those geeks are doubling up!
So we know of at least 2 who are doing chemistry and physics. But it doesn't give much info for math. But it is possible to that they could be. Anyways, I'm curious to see how this is answered. Best of luck.
Oh- Oh "if everybody taking a science is taking a math. mea culpa. it has to be two. I'll bet my next paycheck, lol
2006-09-07 17:34:16 · answer #1 · answered by coffee_addict 3 · 1⤊ 0⤋
math - 82 students
chemistry - 33 students
physics - 27 students
You want to know how many students are taking all three courses?
coffee_addict is correct that there are 58 students all together taking chemistry and physics. Two of them are taking both chemistry and physics, accounting for the total enrollment of 60 in the two courses.
All the students in chemistry and physics are taking math, so those two who are doubling-up are taking chemistry, physcis, and math.
The total number of students taking math is irrelevant. The math students include some who are not taking any science, so who cares? Notice that coffee_addict arrives at the correct answer without using the 82 in any calculation.
Ego's suggestion that you "add them all up" will result in a number much greater than 100, so it is wrong.
Brian F's reasoning is totally wrong. He just threw all the numbers into a pot and stirred them around, adding and subtracting willy-nilly with no good logic.
2006-09-07 17:15:39 · answer #2 · answered by ? 6 · 0⤊ 0⤋
doesn't the text you just typed say that there are 82 people taking math, 33 in chem and 27 in physics? or are you trying to find out how many are in all 3 classes?
2006-09-07 17:16:30 · answer #3 · answered by cinquefoil_solis 3 · 0⤊ 0⤋
100 = survey limit
82 = math
33 = chemistry
27 = physics
42 = not chem or physics
33+27+42 = 102
since 82 kids are taking math, 102- 82 = 20.
therefore 20 kids are in all three classes
2006-09-07 17:23:18 · answer #4 · answered by Brian F 4 · 0⤊ 1⤋
82 peeps in math
33 peeps in chem but everyone taking science is also taking math so you would add 33 to 82 (=115)
27 peeps in physics and same as with the chem peeps, you would add 27 to 115 to get the total number of peeps taking math
Soooo.... total math= 82+33+27
total chem=33
total physics=27
Now add them all up together and that will be the total in math, chem, and physics
2006-09-07 17:28:08 · answer #5 · answered by Anonymous · 0⤊ 1⤋
you threw a curve ball by saying "everyone taking science" Is "science" both physics and chemistry, or just one or the other or what? Are you asking who is taking all three? You appear to have left out a word in the final phrase, I think.
2006-09-07 17:21:29 · answer #6 · answered by paul b 1 · 0⤊ 0⤋
you could feed your canines 17/6 cups of nutrition daily. 17/6 is resembling 2 and 5/6 cups. to discover this huge sort take 4.25 and multiply it by making use of two/3 section subsequently is going to equivalent length cases width. So, A = 9.25 x 8.8 = 80 one.4 in squared
2016-10-14 10:54:46 · answer #7 · answered by pachter 4 · 0⤊ 0⤋
60
2006-09-07 17:21:18 · answer #8 · answered by E D 2 · 0⤊ 1⤋
Ow!
My brain hurts. :(
:P j/k. I'd help you if I could...honest, I would.
2006-09-07 17:14:37 · answer #9 · answered by pacific_crush 3 · 0⤊ 3⤋