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If you are trying to find the limit as x approaches five and you get the fraction to be 0 over 0, the limit doesn't exists, right?

2006-09-07 17:10:04 · 11 answers · asked by Anonymous in Education & Reference Homework Help

11 answers

MAY OR MAY NOT EXIST DEPENDING ON THE KIND OF FUNCTION IT IS.........
but generally it does exist

2006-09-09 00:38:09 · answer #1 · answered by man s 2 · 1 0

There is a theorem that when you have a expression in fraction form, and the limit is indeterminate, a valid limit may sometimes be found by differentiating the numerator and denominator separately, and forming a new fraction with the differentials. If this new expression has a limit, this is also the limit of the original function.

The example that comes to mind is:

lim(sin x / x)|x-->0 is indeterminate.
lim(cos x / 1)|x-->0 = 1.
therefore lim(sin x) = 1
This agrees with the intuitive answer arrived at if you graph the expression.

2006-09-08 00:42:06 · answer #2 · answered by Helmut 7 · 0 0

it is not necessarily right in all cases.... there techniques that can be applied when you get a limit of 0/0... the Le Hospital's rule can be used... but since you did not put the whole equation, i cannot give you a concrete answer...

2006-09-08 00:36:05 · answer #3 · answered by cutie 1 · 0 0

Sometimes the limit does exist.

2006-09-08 00:16:20 · answer #4 · answered by MsMath 7 · 0 0

it depends on the equation. Limits usually refers to parabolic curves where the chart goes infinitely. if you get the equation 0/0, then the limit is undefined, not dne

2006-09-08 00:14:26 · answer #5 · answered by Brian F 4 · 1 1

when i drink there is a limit its about 2/3 of a 5th

2006-09-08 00:14:49 · answer #6 · answered by grandpa40 3 · 0 2

uhhhuhhhhh 1

2006-09-08 00:13:07 · answer #7 · answered by Anonymous · 0 2

yes

2006-09-09 06:47:36 · answer #8 · answered by Red Falcon 1 · 0 0

what is the exact equation? it is true in some cases.

2006-09-08 00:11:50 · answer #9 · answered by Matty G 2 · 1 0

Right!!!!

2006-09-08 00:11:44 · answer #10 · answered by Mickey's gurl 3 · 0 2

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