I am having trouble with this problem.
2006-09-07 15:24:18 · 26 answers · asked by Candiedcherries123 1 in Education & Reference ➔ Homework Help
This was for my daughter's homework problem in 3rd grade.
2006-09-07 16:29:29 · update #1
3 and 337,
any time anumber has digits that add up to a number divisible by 3, that number will be divisible by 3,
1+0+1+1=3
another example... 7521...
7+5+2+1=15,... 1+5=6,
6 is divisible by 3 so 7521 will be divisible by 3
2006-09-07 15:30:40 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3
2006-09-07 22:33:52 · answer #2 · answered by drvshaftdrew 4 · 0⤊ 0⤋
3
2006-09-07 22:26:04 · answer #3 · answered by scubadvr 2 · 0⤊ 0⤋
3
2006-09-07 22:25:30 · answer #4 · answered by Miss T. 2 · 1⤊ 0⤋
Which number does 2 go into? Even or odd?
3- Any number that adds up to 3 is divisible by 3 -15 = 1+5, divisible by 3
5- Must end in 5 or 0 right?
9 What comes after 999?
10 Even or odd?
2006-09-07 22:28:31 · answer #5 · answered by Scott B 3 · 0⤊ 1⤋
the number 3
2006-09-07 22:26:27 · answer #6 · answered by Son Petite Belle 2 · 0⤊ 0⤋
if you do not know how to multiply or divide, then you have a problem. I suggest you start practising. However, if you divide 1011 by 2, 5, 9, and 10 you will have a remainder. But if you divide it by 3, there is no remainder. So the answer is 3. Try long division. Bye the way, I hope you are joking.
2006-09-07 22:39:57 · answer #7 · answered by Reidi 3 · 0⤊ 0⤋
If it's divisible by 2, then it would be even. It's odd, so it's not.
If it's divisible by 3, then its digits will add up to a number divisible by 3. 1+0+1+1=3, which is divisible by 3, so 1,011 is, too.
If it was divisible by 5, it would end in a 5 or a 0. It doesn't, so it's not.
If it was divisible by 9, its digits would add up to a number divisible by 9. It adds up to 3 (see above), which is not divisible by 9, so 1,011 is not either.
If it was divisible by 10, it would end in a 0. It doesn't, so it's not.
Think logically, and you can do these things yourself.
2006-09-07 22:28:46 · answer #8 · answered by BoredBookworm 5 · 0⤊ 1⤋
3
All numbers that are divisible by 2 end with 0,2,4,6, or 8, so it's not that.
Numbers are divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 so the number 3627 is evenly divisible by 3.
All numbers that are divisible by 5 end in 0 or 5, so that's not it.
Numbers are divisible by 9 if the sum of all the individual digits is evenly divisible by 9. For example, the last sum of the digits of the number 3627 is 18, which is evenly divisible by 9 so 3627 is evenly divisible by 9
Numbers that are divisible by 10 end in 0.
2006-09-07 22:25:31 · answer #9 · answered by DanE 7 · 1⤊ 0⤋
Try 3. 337 Times.
2006-09-07 22:27:24 · answer #10 · answered by eddie_schaap 4 · 0⤊ 0⤋