3x + 1 < -35 or -2/3x *less than or equal to* 6
2006-09-07 15:16:51 · 5 answers · asked by Rachel 1 in Science & Mathematics ➔ Mathematics
Part One ;
3x + 1 < -35
3x < -35 - 1
3x < -36
x < -36/ 3
x < -12
Part Two;
-(1) * (- (2/3)x ≤ 6)
+2x ≥- 6* 3
+2x ≥ 18
x ≥ 18/(-2)
x ≥ -9
Good Luck
2006-09-08 04:44:26 · answer #1 · answered by sweetie 5 · 1⤊ 0⤋
OK.
3x + 1 < -35 (subtract 1 from both sides)
3x < -36 (divide both sides by 3)
x < -12
-2/3 x ⤠6 (multiply both sides by 3)
-2x ⤠18 (divide both sides by -2)
x ⥠-9
Doug
2006-09-07 22:25:14 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
x<-11 1/3
x<=-9
2006-09-07 22:30:27 · answer #3 · answered by ja\\James W 1 · 1⤊ 0⤋
3x + 1 < -35
3x < -36
x < -12
---------------------------
(-2/3)x <= 6
-2x <= 18
x >= -9
2006-09-07 22:45:04 · answer #4 · answered by Sherman81 6 · 1⤊ 0⤋
Give me more details.
2006-09-07 22:30:01 · answer #5 · answered by sdt1979 2 · 1⤊ 0⤋