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A gallon of paint can cover 400 square feet. To the nearest half gallon, find how much paint will be needed to paint two coats on the walls and ceiling of a room that is 20 feet long, 18 feet wide, and 8 feet high.

2006-09-07 14:47:08 · 15 answers · asked by jason 1 in Science & Mathematics Mathematics

15 answers

Assuming no windows or doorways, there are 2 walls that have an area of 20*8 and 2 that are 18*8. That creates a total area of:

160*2 + 144*2 = 608 square feet

The ceiling adds 20*18 = 360 square feet

Total per coat is 968 square feet.

Multiply that by 2 for 2 coats:

2*968 = 1936

Divide that by 400 and the nearest half gallon is 5.0 gallons
(4.84 rounded to the nearest .5)

2006-09-07 14:53:53 · answer #1 · answered by RR 2 · 0 0

First find the area your going to paint. This would be the surface area of the room (all the walls plus the ceiling).

The walls are all 8 feet high. Two of the walls are 18 feet wide, and two are 20 feet wide. To get the areas of the four walls, then, two are 8ft by 18 ft, and two are 8 ft by 20 ft.
2 x 8 x 18 + 2 x 8 x 20 =
288 + 320 =
608 square feet.

Since the ceiling is 20 ft by 18 ft or 360 square feet, this means there's a total paintable area of 608 + 360 = 968 square feet. Since we want two coats, you must double it to 1936 square feet.

For this much surface area you'll need 1936/400 = 4.84 gallons. Since you can only buy full gallons, you'll need 5 gallons of paint.

2006-09-07 21:55:27 · answer #2 · answered by froggyj5 3 · 0 0

First you need to find the different area in sq.ft.

Therefore

the area of the ceiling Ac
Ac= 20*18=360 sq.ft.
the area of the two long side of the room Along are equal
Along1=Along2=20*8=160 sq.ft.
the area of the two short sides equal Ashort
Ashort1=Ashort2=18*8=144 sq.ft.

total area to be painted is Atotal
Atotal=360+2*160+2*144=968sq.ft.

two coats 968*2=1936sqft

since one gallon paints 400 sq.ft.
then 1936/400=4.84 gallons

the answer is needed to the nearest half gallon so
5.0 gallons of paint is needed.

2006-09-07 22:03:47 · answer #3 · answered by dk 2 · 0 0

Let's first find the total paintable area of the room, assuming all four walls need paint. Two walls have an area of (20 ft x 8 ft), or 160 square feet. This is because they're 20 feet long and 8 feet high. The other two walls have an area of (18 ft x 8 ft), or 144 square feet. This is because they're 18 feet wide and 8 feet high. The ceiling has an area of (20 ft x 18 ft), or 360 square feet. This is because its 18 feet wide and 20 feet long. Adding these areas together (2 walls x 160 square feet per wall + 2 walls x 144 square feet per wall + 1 ceiling x 360 square feet per ceiling) yields a total paintable area of 968 square feet. Since we're giving it two coats, we double this number, giving us 1936 square feet. To get the number of gallons of paint, we can divide this total by the conversion ratio (400 square feet per gallon) to give us a numerical answer of 4.84 gallons. Rounding to the nearest half-gallon gives us...5 gallons.

2006-09-07 21:56:28 · answer #4 · answered by galaxy625 2 · 0 0

You have 2 walls @ 8x18,
2 walls @ 8x20,
and a ceiling that is 20x18.

The first two walls are 8x18 = 144 ft² x 2 = 288 ft².
The next two walls are 8x20 = 160 ft² x 2 = 320 ft².
The ceiling is 20x18 = 360 ft².

For 1 coat of paint, that's 288+320+360 = 968 ft².
Multiply by two for the second coat = 968x2 = 1936 ft².

So that's a total of 1,936 ft² that is needing to be painted.

If 1 gallon of paint covers 400 ft², then divide the total area to be painted by that: 1936/400 = 4.84, or to the nearest half gallon, 5 gallons.

You'll need 5 gallons of paint to cover that area.

2006-09-07 22:02:48 · answer #5 · answered by Anonymous · 0 0

What ever we get for an answer will be doubled because we're putting two coats on.

Let's figure the walls first:
The 20 ft walls are: 20 (8) (2)=320 sq ft
The 18 ft walls are: 18 (8) (2)=288 sq ft
The ceiling is: 18(8)=144 sq ft

Add 'em up: 320+288+144=752 sq ft
Remember, two coats: 2 (752)=1504 sq ft

Each gal covers 400 sq ft so:
1504/400=3.76 gallons

We will need 4 gallons (to the nearest 1/2 gal.)

This is the kind of math you will use if you ever do any home improvement or repairs.

2006-09-07 22:02:15 · answer #6 · answered by LeAnne 7 · 0 0

Ceiling 18X20 = 360
Walls 18 X 8 =144 X2 = 288
and 20 X 8 = 160 X 2 = 320

The total is 968 SQUARE FEET times 2 is 1936 SQUARE FEET divided by 400 = 4.84 so you have to buy 5 gallons of paint.

2006-09-07 21:56:47 · answer #7 · answered by MollyMAM 6 · 0 0

Paint covers the surface, yes? So you need to find the surface area to be covered.

Assuming the room is rectangular, you will have two walls that are 20 feet by 8 feet, two walls that are 18 feet by 8 feet, and one ceiling that is 20 feet by 18 feet. Find the areas involved and add them together. Since you want two coats, multiply by 2. Then, take the result and divide by 400 (the area covered by one gallon of paint) and that will be the number of gallons you need. Round up to the nearest half-gallon: for instance, if you end up with 2.35 gallons, you'll need 2.5 gallons of paint.

2006-09-07 21:54:43 · answer #8 · answered by Anonymous · 0 1

find the perimeter: 20+20+18+18=76feet
find the area: 76feetX8feet=608 sq feet

1 gal @ 400sq ft
208 feet left so 208/400=.52, or 52% of a gallon (half gallon)
Times 2 (for 2 coats) so about 3 gallons of paint.

LOL and then the ceiling...

20X18=360 sq feet, for 2 coats (640 sq ft), you'll have to add another 2 gallons of paint

GRAND TOTAL: 5 gallons!

2006-09-07 21:56:42 · answer #9 · answered by ? 2 · 0 1

Total area =
(18*8) 2 + ( 20*8) 2 + (20*18 ) = 968

for double coating = 968 * 2 = 1936

400 sq ft require 1 gal
=> 1sqft. require 1/400 gal
=> 1936 sq ft require 1936/400 = 4.84 gal

2006-09-07 22:22:38 · answer #10 · answered by pradyumna s 1 · 0 0

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