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What are the vertices and asymptotes of this hyperbola?
(((x+2)^2)/9)-(((y+3)^2)/25)

2006-09-07 14:35:34 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

I hope you are asking for (((x+2)^2)/9)-(((y+3)^2)/25)=1!

Look at it as [(x- -2)/3]^2-[(y- -3)/5]^2=1.

The center is (-2,-3).

The asymptotes (in point-slope form) are y+3=+/- 5/3(x+2).

If you intended something other than =1 at the end, the above is all wrong! :)

2006-09-08 01:04:10 · answer #1 · answered by Anonymous · 0 0

The center is (-2,-3)

The asymtotes are y = +/- 5/3x

The vertices are 3 to the right and left of center so they are: (1,-3) and (-5,-3)

2006-09-07 15:06:24 · answer #2 · answered by MollyMAM 6 · 0 1

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