scattered around the house are 100 nuts in 5 bowls. the 1st and the 2nd bowl together contain 48 nuts. The 2nd and 3rd bowls together contain 34. THe 3rd and 4th bowls together contains 30 nuts. The 4th and 5th bowls together contain 48 nuts. How many are in each bowl?
2006-09-07 14:34:04 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
3rd bowl has 4... 4th bowl has 26 5th bowl has 22, 2nd bowl has 30, and the 1st bowl has 18
2006-09-07 14:36:54 · answer #1 · answered by Anonymous · 2⤊ 0⤋
John J is correct
1st 18 A
2nd 30 B
3rd 4 C
4th 26 D
5th 22 E
18+30+4+26+22=100
there are many ways of doing it. But first label the bowls in order A,B,C,D
A+B = 48
D+ E = 48
(A+B)+C+(D+E) = 100
48 + C + 48 =100
C + 96 = 100
c = 4
Now you have one and can solve the next two
B+C =34
B+4 = 34
B = 30
C+D = 30
4+D=30
D=26
Then the first and last one:
A+B=48
A+30 =48
A=18
D+E=48
26+E=48
E=22
2006-09-07 14:42:11 · answer #2 · answered by JuanB 7 · 0⤊ 0⤋
I must be reading this wrong, you have only 100 nuts right? in 5 bowls? you question is either wrong or you listed it incorrectly. because it just don't add up.
I had to re- read this, Man I must be old. I get it, sorry you did it right. Sorry, I will show this to my 11year old and 8 year old. Thanks Dave
2006-09-07 14:39:38 · answer #3 · answered by duster360 4 · 0⤊ 0⤋
i have no idea but thats a great riddle im emailing it to my math teacher here another riddle: two boys wanted to buy a candy bar. one boy was two cents short the other boy was twenty-four cents short. when they put their money together they still didnt have enough to buy the candy bar. how much was the candy bar?
2006-09-07 14:40:57 · answer #4 · answered by Colin Night 2 · 0⤊ 0⤋
1st: 24
2nd: 24
3rd: 10
4th: 20
5th: 48
2006-09-07 14:39:50 · answer #5 · answered by Lady 2 · 0⤊ 0⤋