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n^2 + 6n + 5 = ?

2006-09-07 13:14:48 · 10 answers · asked by Anonymous in Education & Reference Homework Help

10 answers

n^2 + 5n + n + 5 =
n( n + 5 ) + 1(n + 5 ) =
(n + 5 ) ( n +1 )

2006-09-07 13:22:41 · answer #1 · answered by saahil 4 · 0 0

You need to learn how to work these problems on your own....

That said, n^2 + 6n + 5 = (n+1)(n+5)

Cross products is 6n and the constant is 5...so the above is indeed correct!

2006-09-07 20:21:32 · answer #2 · answered by alrivera_1 4 · 0 0

seperate n from the rest of the equation
n^2 + 6n + 5 =
- 5
n^2 + 6n = -5
___ ___
6 6 (align under each side of equation)
n^2 + n = -5/6
taking the square of a squared # cancels the square but also take square of other side so n + n = the square root of -5/6
2n = the square root of -5/6
divide both sides by 2 and there's your answer
n = the square root of -5/12

2006-09-07 20:24:45 · answer #3 · answered by answerseeker 2 · 0 0

I wont answer it but I'll tell you how to answer it.

Factor it so it looks like

(n+a)*(n+b)=0. Then n will equal -a and -b.

To find a and b, fin some numbers so that a*b=5 and a+b=6.

For example, if it was

n^2 + 26n + 25 =0, you'd set up (n+a)(n+b)=0.
Now 25=5*5, but 5+5 is not equal to 10, so thats wrong.
25=25*1, and 25+1=26, so that works!

So that question would be (n+25)*(n+1)=0, and n=-25 and n=-1.

Word.

2006-09-07 20:22:56 · answer #4 · answered by john_lewin 2 · 0 0

(n+5)(n+1)

2006-09-07 20:21:51 · answer #5 · answered by martinashasha 2 · 0 0

(n+5)(n+1)

2006-09-07 20:16:32 · answer #6 · answered by ♥James 2:19♥ 4 · 0 0

7n+5

2006-09-07 20:20:29 · answer #7 · answered by aliali1282002 2 · 0 1

omg thats so easy but sorry i dont tell ppl answers on the computer

2006-09-07 20:16:06 · answer #8 · answered by badgirl10134 2 · 0 0

you need help with that!!!! you must not pay a lick of attention in class!!!!!

2006-09-07 20:17:54 · answer #9 · answered by Sady 2 · 0 0

badgirl10134 probably doesn't know (that's why she can't answer.)

2006-09-07 20:17:26 · answer #10 · answered by lil mamma 2 · 0 0

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