A number n where if the sum of the digits of the number is divisible by n, then the number itself is divisble by n.
2006-09-07 12:29:25 · 5 answers · asked by Arie B 1 in Education & Reference ➔ Homework Help
A number n will always be divisible by n....
I believe you're thinking of 3? If the sum of a number's digits is divisible by 3, then the number itself is divisible by 3.
This also works with 9. If the sum of a number's digits is divisible by 9, then the number itself is divisible by 9.
2006-09-07 12:36:02 · answer #1 · answered by hawk22 3 · 0⤊ 0⤋
Hmm this is a toughie which actually doesnt make that much sense, what you are saying is A number for example 123, Then you want the sum of the digits so 1 + 2 + 3 = 6, But then you say the product you get from that which is 6, can be divided by the original number 123, which is clealry not possible because no matter what number there is no way the sum of the digits can be divided by the original number, i think you worded the question a little wrong, Check over the Variable N you are using, maybe theres more then one or something
2006-09-07 19:40:46 · answer #2 · answered by ? ? 2 · 0⤊ 0⤋
I'm not sure about your use of n.. but...
if you take a number like 81 and total up the separate digits you get 9... 9 is divisible by 3 and by 9... and so is 81...
this will also work for any number that the digits total up to 9...
1233 is also divisible by 3 and by 9
2006-09-07 19:36:41 · answer #3 · answered by ♥Tom♥ 6 · 0⤊ 0⤋
Does the number have to have more than one digit?
2006-09-07 19:34:48 · answer #4 · answered by Black Sabbath 6 · 0⤊ 1⤋
Three, or Nine
2006-09-07 19:35:07 · answer #5 · answered by nikkoj1975 4 · 0⤊ 0⤋