math hwk help PLEASE!?!?

Question

before you go smart mouthing me, i just want to say that i dont understand these questions.

express inradical form the length of an equaliateral triangle whose sides has the unit length of ...

[question 1] 10
[question 2] 4
[question 3] N

and ...

what is the length of a side of a square whose diagional is 4?

Answer 1

Do you mean the area of each of the triangles? If so, then:

(1)
First calculate the height x of the triangle.
10² = x² + 5²
100 - 25 = x²
x = √(75)
Area = ½ b * h
Area = ½(10)(√(75))
Area = 42∙30127019 units square.

Question (2) is done in a similar way.

(3)
First calculate the height x of the triangle.
N² = (½N)² + x²
N² - (½N)² = x²
N² - (1/4)N² = x²
(3/4)N² = x²
x = √(3/4)N²

Area = ½ b * h
Area = ½(N)(√(3/4)N²) Square units.

(4)
The sides of a square are equal in length.
4² = x² + x²
4² = 2x²
16 = 2x²
16/2 = x²
8 = x²
x = √8
x = 2∙828 427 125

Answer 2

ok, the first question does not make sense. Are you sure they want to know the "length" of a triangle? Is there a picture? The length would just be the length of one of the sides. Maybe they want the length of the perimeter of the triangle?

Anyway, the second one makes more sense. if the square has a diagonal of 4, the length of the sides can be calculated using the identity associated with the lengths of any right triangle A^2 +B^2 = C^2 . Since all sides must be equal (definition of a square) A and B are the same. So we get 2*(A^2) = C^2. And we know C is 4 so C^2 = 16. Substitute this in and we get 2*(A^2) = 16. With some algebra we simplify to A=sqrt(8). Each side is exactly sqrt(8).

Answer 3

need to know which is the hypotenuse for 1,2,3 second
x^2+x^2=4^2 you can solve from their

Message me at [e-mail]

http://www.msnbc.msn.com/id/14717643/from/RS.1/

Answer 4

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