Algebra 2 HElp?

Question

Whats
2b^2-3ab+4a^2

factored out. and how did u do it

Answer 1

thats gonna take a whhile so i dont want to do it

Answer 2

To remove a common factor and rewrite a polynomial as the product of a monomial and another polynomial:
Find the greatest common factor which is a whole number (no variables).
Divide all terms of the polynomial by that factor, and put the result in parentheses. Write the factor outside the parentheses.
Find the greatest common factor which is a variable or a product of several variables. That is, find the variables contained in every term, and write them with their lowest exponent.
Divide each term of the expression in parentheses by the greatest common variable factor, and write the variable factor outside the parentheses.
Check--distributing the monomial over the new polynomial should yield the original polynomial.
Example 1: Factor 4x2 +16x3 + 8x.
The greatest common whole number factor is 4.
4x2 +16x3 +8x = 4(x2 +4x3 + 2x)
The greatest common variable factor is x (x is contained in all the terms, and its lowest exponent is 1).
4(x2 +4x3 +2x) = 4x(x + 4x2 + 2)
Check: 4x(x + 4x2 +2) = 4x2 +16x3 + 8x
Thus, 4x2 +16x3 +8x = 4x(x + 4x2 + 2).
Example 2: Factor 12x3y + 3x4y2 -6x2y2z.
The greatest common whole number factor is 3.
12x3y + 3x4y2 -6x2y2z = 3(4x3y + x4y2 -2x2y2z)
The greatest common variable factor is x2y (x is contained in all the terms, and its lowest exponent is 2; y is contained in all the terms, and its lowest exponent is 1; z is not contained in all the terms).
3(4x3y + x4y2 -2x2y2z) = 3x2y(4x + x2y - 2yz)
Check: 3x2y(4x + x2y - 2yz) = 12x3y + 3x4y2 -6x2y2z
Thus, 12x3y + 3x4y2 -6x2y2z = 3x2y(4x + x2y - 2yz).

Answer 3

(2b 2a)(b 2a)

This is as far as I got because it doesnt seem like the -3ab will help lead to anything

plz post original

Answer 4

There are only three posibilities
(2b-2a)(b-2a)
(2b-a)(b-4a)
(2b-4a)(b-a)

none of them give you -3ab in the middle.

its not factorable

Answer 5

yeah this is not correct..it won't factor out:

figure out ur possibilities...

(2b _a)(b _a)

the #'s in front of the a must multiply to = +4. so ur possiblities are 4,1; 1,4; or 2,2:

(2b - 4a) (b - a) --> -4ab -2ab = -6ab nope!
(2b - a) (b - 4a) --> -ab -8ab = -9ab nope!
(2b -2a)(b-2a) --> -2ab -4ab = -6ab nope!

this is impossible unless there is something missing..

Answer 6

look at the constans multiplying the variables and consider combinations that add up