help finding the horizontal and vertical asymptote?

Question

equation -----> (5-x^2) / (3x^4)

thanks for your help.

Answer 1

Vertical Asymptote:

Set the denominator equal to zero, and solve for 'x'. If the result isn't also a zero for the numerator, you have a vertical asymptote:

0 = 3x^4
x = 0

Check: 5 - (0)^2 ?= 0

No, thus x = 0 is a vertical asymptote.

Horizontal asymptote:

Actually, it's called the end behavior asymptote, and it may or may not be horizontal. Compare the degree of the numerator to the degree of the denominator. There are three cases:

n > d which means there is a end behavior asymptote
n = d which means there is a horizontal asymptote
n < d which means there is the horizontal asymptote y = 0

Degree of numerator = n = 2
Degree of denominator = d = 4
Since n < d, the horizontal asymptote is
y = 0

Check at
http://www.coolmath.com/graphit/

Answer 2

look up on google first, or google Dr.Math, he'll help you