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(x^4 + 2x^2 + 1) / (x^2 - x + 1)

would their not be a vertical asymp.? and how do i find the horiz. asymptote? i know it's from the degree of both the numerator and denominator. thanks for your help.

2006-09-07 10:12:34 · 3 answers · asked by shih rips 6 in Science & Mathematics Mathematics

3 answers

there is no vertical or horizontal asymptote to this function. numerator's degree is higher than the denominator's degree. also since there is no real root for x^2-x+1 so the denominator cannot be 0

2006-09-07 15:17:42 · answer #1 · answered by aznskillz 2 · 0 0

to check for vertical asymptotes set the denominator to zero and solve for x

2006-09-07 10:33:38 · answer #2 · answered by Mike G 1 · 0 0

graph it on a calculator and you can see them

2006-09-07 10:15:10 · answer #3 · answered by Anonymous · 0 0

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