Help me please?

Question

Im not trying to get out of doing my homework or anything but can someone please explain to me how to do this? (Im not looking for the answer) Or how to set up an equation. Be as detailed and clear as possible please!

A merchant has two large barrels. The smaller barrel holds 336 liters but is only five-sixths full of juice. The merchant pours the juice into the larger barrel and finds that the barrel is four-ninths full. How much juice does the large barrel hold when full?

Answer 1

to set up the equation use ratios and cross multiply. put 336 over five sixths and x over four ninths and cross multiply geting-- 5/6x= (336 times 4/9) then divide whats in parenthese by 5/6 AND YOU HAVE YOUR ANSWER

Answer 2

You need to calculate 5/6 of 336. That is how much juice there is. When this is poured into the larger barrel (I'm assuming that the larger barrel was empty until this juice was poured into it, since this is the only way you can answer the question), that barrel is 4/9 full. You want to know what maximum amount the large barrel would hold, which would be 1, or 9/9. You get that by multiplying the amount of juice by 9/4 (4/9x9/4 =1).

Answer 3

let the capacity of the smaller barrel=336 litres
1t holds(5/6) that is (5/6)*336 litres=280 litres
let the capacity of the larger barrel be =x
4/9x=280
multiplying both sides by 9/4
x=280(9/4)=630 litre
so the capacity of the larger barrel is 630 litres

Answer 4

336 x 5/6 = 280 -- this is how much you have in the smaller barrel

280 / 4/9
=280 x 9/4 =630 liters -- this is how much the large one can hold

Answer 5

Ok, w/o giving you any answers or setting up an eq.

You'll need to find out how much juice was in the first barrel. Then take that knowledge to figure out how much the second could hold.

Hint: Use proportions.