long division help?

Question

(x^3 - 1) / (x^2 - 9 )

i know i need to change the "x^3 - 1" to "x^3 + 0x^2 + 0x - 1".
thanks for the help.

Answer 1

you are right
if you want to divide
x^2-9)x^3+0x^2+0x-1(x
x^3 -9x
9x-1
the division will stop as the remainder is of a lesser degree
so the answer is
(x^3-1)/(x^2-9)=x+(9x-1)/(x^2-9)
x is the quotient and 9x-1 is the remainder

Answer 2

you are right
if you want to divide
x^2-9)x^3+0x^2+0x-1(x
x^3 -9x
9x-1
the division will stop as the remainder is of a lesser degree
so the answer is
(x^3-1)/(x^2-9)=x+(9x-1)/(x^2-...
x is the quotient and 9x-1 is the remainder