precal-finding horizontal and vertical asymptotes?

0 ⤊

precal-finding horizontal and vertical asymptotes?

(x^2 - 4) / (x^2)

would the vertical asymp. be 0 and horizontal asymp. be 0?
thanks for the assistance.

2006-09-07 09:43:18 · 2 answers · asked by shih rips 6 in Science & Mathematics ➔ Mathematics

2 answers

your vertical asymptote is correct, but the horizontal one will be the y=1. Since the leading terms have the same degree in the numerator and denominator, the answer is just the ratio of their coefficients.

2006-09-07 09:59:17 · answer #1 · answered by Yelena 1 · 0⤊ 0⤋

yes
y=(x^2 - 4) / (x^2)
=1-4/x^2
x=0 is the vertical asymp
y=0 is the horizontal asymp

2006-09-07 16:55:18 · answer #2 · answered by Amar Soni 7 · 0⤊ 0⤋