i need help?

Question

i need to factor
2xsquared-482x-12144
in this form 2x( )( )

Answer 1

the answer is ;
factor ' -2 '
-2( 241x^2) + 6072)

that's all
good luck.

Answer 2

First pull out the common value of 2:
2 (x + a)(x + b) = 2(x² - 241x -6072)

So you want to end up with a result like:
2(x + a)(x + b)

Expanding this out:
2(x² + (a+b)x + ab)

You can use trial and error to figure out the values or you can use the quadratic formula.

Using trial and error, you want:
ab = -6072
a + b = -241

Prime factors of 6072 are:
± (2 x 2 x 2 x 3 x 11 x 23)

Thus the integer factors (ab) of -6072 are:
-6072, 1
-3036, 2
-2024, 3
-1518, 4
-1012, 6
-759, 8
-552, 11
-506, 12
-276, 22
-264, 23 <---
-184, 33
-132, 46
-92, 66
-88, 69
-69, 88
-66, 92
etc.

Try the sum of each of these and you'll find the right answer is the one I've highlighted:
-264 x 23 = -6072
-264 + 23 = -241

So the final factorization is:
2 (x - 264) (x + 23) = 0

Thus the solutions are:
x = 264 or x = -23

If you use the quadratic formula you'll get:
x = (241 ± sqrt(82369) ] / 2
x = (241 ± 287) / 2
x = 528 / 2 or -46 / 2
x = 264 or -23

So the final factorization would still be:
2 (x - 264) (x + 23) = 0

Answer 3

2 x (x + a ) (x + b)

Answer 4

2(x^2-241x-6072)=2(x-264)(x+23)

Answer 5

2(x^2-241x-6072)=2(x-264)(x+23)

Answer 6

(2x-528)(x+23)=
2(x-264)(x+23)

Answer 7

2x^2-482x-12144
=2(x^2-241x-6072)
=2(x-264)(x+23)