how would you calculate the molarity of the aqueous solution?
a) 72.0 mL of 0.210 M NaOH diluted to 0.230 L with water
(and how many signifant figures would the answer need?)
2006-09-07 05:32:57 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
First, you need to determine how many moles of NaOH are there -->
c=n/v, therefore
n=cv
n=0.210 mol/L * .0720 L
n=0.0151 mol of NaOH
Diluting it, we get
c=n/v
c=0.0151 mol/0.230 L
c=0.0657 mol/L (3 sig figs)
2006-09-07 06:23:25 · answer #1 · answered by The ~Muffin~ Man 6 · 1⤊ 0⤋
Molarity1 x Volume 1 = Molarity2 x Volume2
2006-09-07 13:56:01 · answer #2 · answered by echinate 3 · 0⤊ 0⤋
72 x 0.21 = 230 x M , M is the molarity after dilution
2006-09-07 15:43:35 · answer #3 · answered by basimsaleh 4 · 0⤊ 0⤋
M = moles/L
you get 3 sf
2006-09-07 12:38:20 · answer #4 · answered by shiara_blade 6 · 0⤊ 0⤋