2006-09-07 04:26:57 · 6 answers · asked by dickster00 1 in Science & Mathematics ➔ Physics
Decrease...because outside pressure decreases and baloon expands...lowering inside pressure.
2006-09-07 04:28:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
at sea level the air pressure is 14lbs sq inch, so the balloon is feeling 14 lbs evenly around, also the balloon is made of an elastic material, the pressure on the inside is pushing on the inside surface, keeping the round shape, but also the balloon is trying to squeeze back to it's normal shape.
Now as the balloon rises, the balloon elastic material and the air pressure, is keeping the balloon at it's current shape.
As the balloon rises, air pressure diminishes. now there is less pressure on the balloon pushing in. with less pressure pushing in, the air on the inside now has more room to push out, what used to be 14 lbs now is much less. now the balloon skin will stretch even farther (growing bigger), eventually rupturing.
Try this put a balloon in water, for every 33 feet, the pressure doubles, that means the balloon at 33ft would be half the size.
2006-09-07 11:38:33 · answer #2 · answered by Juggernaut 3 · 1⤊ 0⤋
Decrease of course if you didn't put the balloon inside another bag.
2006-09-07 11:30:35 · answer #3 · answered by dwarf 3 · 0⤊ 0⤋
as the balloon gets higher,the air outside gets thinner,so the ball on will burst,due to increased pressure
2006-09-07 11:31:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
decreases
2006-09-07 11:57:34 · answer #5 · answered by raghulmad 2 · 0⤊ 0⤋
decrease
2006-09-07 11:29:31 · answer #6 · answered by dennis 1 · 0⤊ 0⤋