zinc ore (zinc sulfide) is treated with sulfuric acid, leaving a solution with some undissolved bits of material and releasing hydrogen sulfide gas. if 10.8 g of zinc ore is treated with 50.0ml of sufiric acid (desity 1.1539), 65.1g of solution and undisollved material remains. in addition hydrogen sulfide (density 1.393 g/l) is evolved. what is the volume in liters of this gas?
or how in the world do you figure it out?
2006-09-07 04:19:41 · 3 answers · asked by dizzy 1 in Science & Mathematics ➔ Chemistry
ZnS(10.8 g) + H2SO4(50 ml * 1.1539g/ml=57.695g)
yields HS + 65.1g of solution
10.8g+57.695g-65.1g=3.395g(mass of evolved gas)
3.395g (HS gas) / (1.393g/L) = 2.437 Liters of gas
2006-09-07 04:41:07 · answer #1 · answered by SLKislack 2 · 0⤊ 0⤋
Since you didn't state that the volume was at standard temperature and pressure, you would have to supply that info. in order to calculate the volume of the gas that is evolved. You can do this by using the equation: P1 X V1 divided by T1 is equal to P2 X V2 divided by T2.
Where P is the pressure, V is the volume and T is the temperature in deg. K. Substitute standard pressure for P1, standard temperature for T1 and the volume of the gas for V1. Then by substituting the values for the temperature and pressure at any other set of conditions, you can calculate the value for the volume of the gas at the second set of conditions.
2006-09-07 18:28:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Assume that it's at standard temperature and pressure and use the Universal Gas Law (PV = nrT)
Doug
2006-09-07 11:23:15 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋