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if A is a non-singular square matrix then the inverse of A,denoted by a^-1 is equal to

A^-1=(1/!A!) adj A
method to find the inverse of Square Matrix A.
(1) Evaluate the value of !A! (only if !A! is non zero we can find A^-1)
(2) Find the co factors of elements of matrix A and write down the matrix formed by cofactors of elements A as
A11 A12 A13
A21 A22 A23
A31 A32 A33

(3)write down the adj A as
transpose of
A11 A12 A13
A21 A22 A23
A31 A32 A33

as

A11 A21 A31
A12 A22 A23
A13 A23 A33

(4) By formulawrite down A^-1=(1/!A!)(adj A)

2006-09-07 02:49:34 · answer #1 · answered by raj 7 · 0 0

If you're asking what I think you're asking, ther's a pretty good article on self-commuting metric tensors at
http://en.wikipedia.org/wiki/Metric_tensor


Doug

2006-09-07 09:46:35 · answer #2 · answered by doug_donaghue 7 · 0 0

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