A 8kg box is pushed across a table by a horizontal force F.
A. If the box is moving at a constant speed of 0.350 m/s and the coefficient of kinetic friction is 0.14 what is the magnitude of F?
2006-09-07 01:06:23 · 7 answers · asked by Lorenz 2 in Science & Mathematics ➔ Physics
I need complete solutions pls thanks!
2006-09-07 01:43:23 · update #1
think and feel physics....
in order to have a constant speed the NET force must be zero..either at rest of the sum of the force vectors "add" to zero.
therefore my friend friction must be equal to the force that moves the item
therefore friction = force = 0.14 * 8 * 10 = (coef. * perpendicular wheight to weight component)
constant speed (in direction as well) net forace zero. what aqre the forces?
f you need friction and wieght that cancels with the reaction of the table
did this help?
2006-09-07 01:14:27 · answer #1 · answered by Emmanuel P 3 · 0⤊ 2⤋
At constant speed, the Net Force = 0
Net Force = 0 = Applied force - Friction Force.
(F) Applied Force = Friction Force.
F = mass * g * u(k)
F = 8 (kg) * 9.8 (m/sec^2) * 0.14
= 10.98 (kg*m/sec^2) or 10.98 Newtons.
2006-09-07 11:20:41 · answer #2 · answered by Anonymous · 0⤊ 1⤋
That's actually not an impossible problem. It is very very easy.
The force is 11N.
2006-09-07 01:10:16 · answer #3 · answered by S h ä r k G û m b ò 6 · 0⤊ 1⤋
simple straightforward formula! apply that, and, find the Force yourself: that way, you have the thrill and enjoyment all to yourself! (certainly not impossible, it's a good, fun problem! have fun!)
2006-09-07 01:24:52 · answer #4 · answered by swanjarvi 7 · 0⤊ 2⤋
Read mathematics. It is called multiplication.
2006-09-07 03:25:49 · answer #5 · answered by Dr M 5 · 0⤊ 2⤋
if accelaration is give pls try F=MA
2006-09-07 01:58:02 · answer #6 · answered by SdM 4 · 0⤊ 2⤋
zero................................................. because there is no accelaration.F=MA and a = 0 so force=0
2006-09-07 01:29:38 · answer #7 · answered by Anonymous · 0⤊ 3⤋