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when we weigh an object on a spring balance and on a beam balance,will the readings be same?

2006-09-06 18:57:15 · 7 answers · asked by blossom 3 in Science & Mathematics Physics

please explain ur answer

2006-09-06 19:04:48 · update #1

7 answers

Inertia depends on the mass of the body (i.e. how many protons and neutrons the body contains), not the shape.

Weighing an object on a spring or beam balance will give you the same result, albeit one may be more accurate than the other.

Addendum:

The term "inertia" refers qualitatively to an object's "amount of resistance to change in velocity" (which is determined by its mass), and sometimes its momentum, depending on context (e.g. "this object has a lot of inertia"). Another form of inertia is rotational inertia, which refers to the fact that a rotating rigid body maintains its state of uniform rotational motion. Moment of inertia quantifies the rotational inertia of a rigid body, i.e. its inertia with respect to rotational motion, in a manner somewhat analogous to how mass quantifies the inertia of a body with respect to translational motion.

Rotational inertia does depend on the shape of the body because rotation occurs about a particular axis, and the further away the mass is from the axis of rotation, the greater the rotational inertia. So if you have two objects of the same mass both rotating about their center of gravity, but one body is a ring with a large radius and the other object a sphere with a smaller radius, the ring will have a greater rotational inertia.

2006-09-06 18:59:10 · answer #1 · answered by PhysicsDude 7 · 0 0

1) no, but moment of inertia does.
2) You cannot weigh anything on a beam balance. A beam balance determines mass, not weight. Unfortunately, beam balances and their test "weights" are labeled incorrectly in weight units instead of mass units.

A beam balance will agree with a spring scale at 6AM and 6PM LMT if both are properly calibrated and they haven't been moved appreciably N or S from their calibration site. You weigh more at the poles than you do at the equator. You also weigh more at midnight than you do at noon The diurnal difference at 45 deg. N latitude is approx +/- .04% which is considered to be negligible for most applications. You also weigh less when the Moon is at zenith than when it is at nadir.

2006-09-06 19:55:03 · answer #2 · answered by Helmut 7 · 0 0

shape does matter in some cases. it plays into what is called the moment of inertia. moving in a straight line, shape doesnt matter. when rotating, shape is everything. there are equations for every shape available out there, from solid balls to hollow balls to rings to cylinders to boxes to I beams, etc. mass goes into every moment of inertia equation as well, along with the radius.

yea the reading should be the same

note: everyone decidied to add moment of inertia after I did initially. I win :)

2006-09-06 19:01:45 · answer #3 · answered by sexydp 3 · 0 0

In translational motion inertia is independent of shape...Inertia is the quantitative measure of mass.
But in case of rotational motion it does depend on shape...& that quantity is referred as MOMENT OF INERTIA symbolized as "I" & the realtion is I=mr(square) So this quantity moment of inertia is different for disc,loop,bar & rod etc...
& yes weight is absolutely independant of shape, whatever the shape maybe but if the composition material packed inside it is same then there will be no variation in weight of an object having two different shapes...

2006-09-06 20:02:09 · answer #4 · answered by Sohail Ahmed 1 · 0 0

When I saw this poisonous snake in the bushes Inertia travelled all over my body. so it must have taken its shape.

2006-09-06 22:16:32 · answer #5 · answered by goring 6 · 0 0

Inertia is proportional to mass .it does not depend on shape

2006-09-06 20:14:10 · answer #6 · answered by Anonymous · 0 0

No. It is proportinal to the mass

2006-09-06 19:02:04 · answer #7 · answered by Dr M 5 · 0 0

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