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I been solving it but if supposed to turn out to be a fibonacci. i cant get it to turn out that way.

2006-09-06 17:13:31 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

i fiqured it out. its 3Fn=F(n+2) + F(n-2)

2006-09-06 18:52:56 · update #1

8 answers

Start off with the first few terms and prove it by induction.

F(n+2) + F(n-2) = 3F(n)


Doug

2006-09-06 17:43:56 · answer #1 · answered by doug_donaghue 7 · 0 0

r u joking or are u really serious
look if F(x) = 1
then F(n+2) + F(n-2) =1 +1 =2
if F(x) = x
then F(n+2) + F(n-2) =x-2 + x+2 =2x
if F(x) =x^2
then F(n+2) + F(n-2) =(x+2)^2 + (x-2)^2 = 2x^2+8
actually u hve to tell wht is on right hand side
ur qurestion is incomplete beacause every equation must have well defined left and right handed sides ,have u read chapter on linear equations.Go and read it first.

2006-09-07 03:04:19 · answer #2 · answered by vijay agrawal 1 · 0 0

One possibility - what is F(x)?
Another possibility - define F(0)

When n = 0, you have F(2) + F(-2)
When n = 2, you have F(4) + F(0)

Obviously you have quite a few unknowns to figure out.

2006-09-07 00:19:55 · answer #3 · answered by Anonymous · 0 0

Fibonacci sequence
F(1) = 1
F(2) = 1
Then F(n) = F(n-1) + F(n-2) for n > 2

Is that what you were looking for?

2006-09-07 00:24:15 · answer #4 · answered by Demiurge42 7 · 0 0

Not possible to complete. You need something on the "other side" of the equation providing a constant starting point.

2006-09-07 00:17:43 · answer #5 · answered by Weatherman 2 · 0 0

F (n+2) + F (n-2) = F (2n)
try it for any F(n)....
any way the question is not complete
so it's a wrong answer!

2006-09-07 01:02:23 · answer #6 · answered by M. Abuhelwa 5 · 0 0

Zero?

2006-09-07 00:15:34 · answer #7 · answered by Anonymous · 0 0

Fn+F2+Fn-F2

thus, 2(Fn)

2006-09-07 00:20:47 · answer #8 · answered by Jimmy P 2 · 0 0

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