Anyone good at geometry?

Question

So, here's the problem:

The Department of Parks and Recreation wants to pave a path that goes through the park at a diagonal from corner to corner (the diagram shows the park as 780 ft by 410 ft). How long will the path be?

Thanks.

Answer 1

69

Answer 2

This is a simple Pythagorean equation problem to figure the hypotenuse of the two triangles the path divides the park into.

780 squared + 410 squared = the path length squared. So the path length squared = 776500, so the path length is 881.19237 ft.

Answer 3

Ignore the people quoting Pythagorus - UNLESS the park is a rectangle (which can NOT be assumed from your statement "(the diagram shows the park as 780 ft by 410 ft). "). If it's a paralleolgram, A^2+b^2=C^2 doesn't work.

DOH !

Answer 4

use the pythagorean theorem. Since the park shows a rectangle (length by width; 780ft by 410ft) And they want a diagonal line from corner to corner, (SPLITTING the rectangle diagonally makes a triangel) SO just in case you dont remember the pythagorean theorem.Here it is.

a² + b² = c²
780² + 410² = c²

Answer 5

L=length=780
W=width=410
D=diagonal=the squre root of (780^2+410^2)

Remember this is always the case when calculating the diagonal of a right-angle triangle

Answer 6

780^2 + 410^2=c^2

Im not going to solve this for you. You are on your own for getting an answer. But this is the setup though.

Answer 7

pythagorean theorum
780^2+410^2=c^2
solve for c

Answer 8

Pythagorean Theorem

a^2 + b^2 = c^2

'a' and 'b' are your legs, and c is your hypotenuse of a right triangle.