If the ball is four feet high when it leaves your hand, and if you're using that as the zero point, then the height will be -4 feet when it hits the ground. It's a lot more common to use the ground as a reference, in which case the height is 0 when it hits the ground.
Are you sure you're reading the question correctly?
2006-09-06 16:12:59
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answer #1
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answered by Anonymous
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ok well if the ball is 4 ft b4 u throw it up in the air then u gotta calculate it in the formula...but if its the height on the ground its 0. the question doesnt make any sense. are you sure they arent asking for the time it takes to be thrown up in the air and hit the ground?
2006-09-06 16:11:54
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answer #2
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answered by angelgirl052591 1
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40 5 = -19 + d first you bypass the -19 to the different part once you do you'd be desiring to modify the negetive right into a favorable (every time you bypass something to the different part of the equivalent signal you may want to change the operation) 40 5 + 19 = d now subtract both sixty 4 = d now you've your answer =)
2016-11-25 01:41:08
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answer #3
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answered by Anonymous
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it is assuming that the ground is at 0? so if it hits the ground, then it's also 0. is that a trick question? 8th grade math? wow...
2006-09-06 16:14:36
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answer #4
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answered by Ning 3
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trick question. If you assume the ground is height zero, the height is zero.
2006-09-06 16:11:26
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answer #5
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answered by wildstar_2 6
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What does each variable stand for. Refresh my memory. It's been a while.
height = h
v = velocity? (40ft/s)??
t = time?
2006-09-06 16:11:05
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answer #6
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answered by jbb316 2
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that doesn't sound like 8th grade math
2006-09-06 16:09:26
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answer #7
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answered by Leeda 3
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When the ball hist the ground the height is zero. Duh, the ball is on the GROUND!!!!
2006-09-06 16:11:54
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answer #8
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answered by Anonymous
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plug it into a calculator.
2006-09-06 16:08:47
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answer #9
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answered by Anonymous
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this is not 8th grade homework...you sure you right grade....
2006-09-06 16:16:03
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answer #10
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answered by de_dark_angel71 3
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