guys this is an algebra question, if you can take time to think about it?

Question

the problem is 5x^2 y^2 + 9xy - 2. I need to factor it and find the Gcf if there is one, or factor it someway..

The ^ stand for exponents and 5x^2 y^2 is one whole piece.
If you can take time and try it on paper, youll see i get stuck because of that 2 at the end.

Answer 1

(5xy-1)(xy+2) Check by FOIL; it works.

Answer 2

You should be able to do your own homework. Look at the combinations of the factors of the leading and trailing coefficients; in this case, {5,1} for the leading, and {(+ or -)2,(- or +)1} in the trailing. Use combinations of these multiplied together and added to get +9. In this case, 5*2 + 1*(-1) = 9, so you need 5 to be opposite 2 and 1 to be opposite -1.

The answer is (5xy - 1)(xy + 2).

Do your hw. math is easy.

Answer 3

To factor the equation, you can make it easier if you assume that xy = a

So the eqn becomes 5a^2 + 9a - 2
Then factrorize the eqn:
5a^2 + 10a - a - 2
5a(a + 2) - 1(a + 2)
(a + 2) (5a - 1)

So a = -2 or a = 1/5

substitute back a = xy
Then you get xy = -2 or xy = 1/5

Answer 4

Have you really tried this one? If I gave you 5z^2+9z-2 could you factor that? In this case think of xy as just one unit. In fact it may help you to substitute z for xy. Once you have done the factoring just replace every z with an xy. Good luck, I hope this helped, the question is not difficult once you've gotten past the xy thing.